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Black_prince [1.1K]
3 years ago
9

Suppose the population of the world now is 4 billion and its doubling period is

Mathematics
1 answer:
OleMash [197]3 years ago
8 0

Answer:

4096b after 350 years, 4194304b after 700 years, and 4294967296b after 1050 years. 0.000433065 sq ft. per person after 1050 years making earth uninhabitable.

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Use the numbers 6 2 9 5 2 3<br> to make 36.
VashaNatasha [74]

Answer:

6+2+9+5+2+3+6+3 = 36

Step-by-step explanation:

If you like my answer than please mark me brainliest

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Ben is making math manipulatives to sell. He wants to make at least $450. Each manipulative costs $18 to make. He is selling the
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Identify the solution set of the given inequality using the given replacement set.   x &gt; –4; {–8, –4.3, –4 –3.8, 1.2, 3}  
Dovator [93]
<span>x> -4 means that it is needed to find all the values that are greater than -4 "not including" -4 ... for negative values as you get from zero the values decrease which means that -8 is less than -7 and -7 is less than -6 etc.. and positive values are trivially known to be greater than negative ones then take each value and compare it with -4 -8 is less than -4 -4.3 is less than -4 -4 is equal to -4 which is not included in our required range which is x>-4 -3.8 is greater than -4 which will get in our solution 1.2 is greater than -4 3 is also greater than -4 So our final solution will be {-3.8,1.2,3} Which is B in our question Hope this helps :) Let me know too if you got it :) </span><span>
</span>Answer: C. {-3.8, 1.2, 3}

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3 years ago
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Flura [38]

Answer:

x=13

Step-by-step explanation:

15x-15

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3 0
3 years ago
Read 2 more answers
Maths functions question!!
Marina86 [1]

Answer:

5)  DE = 7 units and DF = 4 units

6)  ST = 8 units

\textsf{7)} \quad \sf OM=\dfrac{3}{2}\:units

8)  x ≤ -3 and x ≥ 3

Step-by-step explanation:

<u>Information from Parts 1-4:</u>

brainly.com/question/28193969

  • f(x)=-x+3
  • g(x)=x^2-9
  • A = (3, 0)  and C = (-3, 0)

<h3><u>Part (5)</u></h3>

Points A and D are the <u>points of intersection</u> of the two functions.  

To find the x-values of the points of intersection, equate the two functions and solve for x:

\implies g(x)=f(x)

\implies x^2-9=-x+3

\implies x^2+x-12=0

\implies x^2+4x-3x-12=0

\implies x(x+4)-3(x+4)=0

\implies (x-3)(x+4)=0

Apply the zero-product property:

\implies (x-3)= \implies x=3

\implies (x+4)=0 \implies x=-4

From inspection of the graph, we can see that the x-value of point D is <u>negative</u>, therefore the x-value of point D is x = -4.

To find the y-value of point D, substitute the found value of x into one of the functions:

\implies f(-4)=-(-4)=7

Therefore, D = (-4, 7).

The length of DE is the difference between the y-value of D and the x-axis:

⇒ DE = 7 units

The length of DF is the difference between the x-value of D and the x-axis:

⇒ DF = 4 units

<h3><u>Part (6)</u></h3>

To find point S, substitute the x-value of point T into function g(x):

\implies g(4)=(4)^2-9=7

Therefore, S = (4, 7).

The length ST is the difference between the y-values of points S and T:

\implies ST=y_S-y_T=7-(-1)=8

Therefore, ST = 8 units.

<h3><u>Part (7)</u></h3>

The given length of QR (⁴⁵/₄) is the difference between the functions at the same value of x.  To find the x-value of points Q and R (and therefore the x-value of point M), subtract g(x) from f(x) and equate to QR, then solve for x:

\implies f(x)-g(x)=QR

\implies -x+3-(x^2-9)=\dfrac{45}{4}

\implies -x+3-x^2+9=\dfrac{45}{4}

\implies -x^2-x+\dfrac{3}{4}=0

\implies -4\left(-x^2-x+\dfrac{3}{4}\right)=-4(0)

\implies 4x^2+4x-3=0

\implies 4x^2+6x-2x-3=0

\implies 2x(2x+3)-1(2x+3)=0

\implies (2x-1)(2x+3)=0

Apply the zero-product property:

\implies (2x-1)=0 \implies x=\dfrac{1}{2}

\implies (2x+3)=0 \implies x=-\dfrac{3}{2}

As the x-value of points M, Q and P is negative, x = -³/₂.

Length OM is the difference between the x-values of points M and the origin O:

\implies x_O-x_m=o-(-\frac{3}{2})=\dfrac{3}{2}

Therefore, OM = ³/₂ units.

<h3><u>Part (8)</u></h3>

The values of x for which g(x) ≥ 0 are the values of x when the parabola is above the x-axis.

Therefore, g(x) ≥ 0 when x ≤ -3 and x ≥ 3.

8 0
1 year ago
Read 2 more answers
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