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san4es73 [151]
2 years ago
9

Nhich net force is larger? 1M/S,20 KG or 10 M/S, 1 KG

Mathematics
1 answer:
lakkis [162]2 years ago
7 0

Answer:

39

Step-by-step explanation:

not right just need points

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1200 resulted $11.88 interest for 23 days. What is the interest rate
Lunna [17]

now, let's notice that 23 days is not even a month let alone a year, assuming there are 365 days in a year, then 23 days is really 23/365 of a year.

\bf ~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\dotfill&\$11.88\\ P=\textit{original amount deposited}\dotfill & \$1200\\ r=rate\to r\%\to \frac{r}{100}\\ t=years\dotfill &\frac{23}{365} \end{cases}

\bf 11.88=(1200)(r)\left(\cfrac{23}{365} \right)\implies 11.88=\cfrac{(1200)(23)r}{365}\implies 11.88=\cfrac{27600r}{365} \\\\\\ 4336.2=27600r\implies \cfrac{4336.2}{27600}=r\implies 0.157\approx r \\\\\\ \stackrel{\textit{converting that to a percentage}}{0.157\cdot 100 \approx r}\implies \stackrel{\%}{15.7}\approx r

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3 years ago
describe why it might not be a good idea to use a key where each symbol stands for 1 in a picture graph
julsineya [31]

It is not a good idea to use a key in a picture graph because it will give you the answer, and you will not have to do as much work and you won't understand how you got that answer.


8 0
3 years ago
You are given that sin(a)=8/17, with a in quadrant ii, and sin(b)=−5/13, with b in quadrant iii. find cos(a−b)
masha68 [24]
1.5 is the answer too your question sir thanks.
5 0
3 years ago
On a certain​ route, an airline carries 7000 passengers per​ month, each paying ​$30. A market survey indicates that for each​ $
KengaRu [80]

Answer:

The ticket price that maximizes revenue is $50.

The maximum monthly revenue is $250,000.

Step-by-step explanation:

We have to write a function that describes the revenue of the airline.

We know one point of this function: when the price is $30, the amount of passengers is 7000.

We also know that for an increase of $1 in the ticket price, the amount of passengers will decrease by 100.

Then, we can write the revenue as the multiplication of price and passengers:

R=p\cdot N=(30+x)(7000-x)

where x is the variation in the price of the ticket.

Then, if we derive R in function of x, and equal to 0, we will have the value of x that maximizes the revenue.

R(x)=(30+x)(7000-100x)=30\cdot7000-30\cdot100x+7000x-100x^2\\\\R(x)=-100x^2+(7000-3000)x+210000\\\\R(x)=-100x^2+4000x+210000\\\\\\\dfrac{dR}{dx}=100(-2x)+4000=0\\\\\\200x=4000\\\\x=4000/200=20

We know that the increment in price (from the $30 level) that maximizes the revenue is $20, so the price should be:

p=30+x=30+20=50

The maximum monthly revenue is:

R(x)=(30+x)(7000-100x)\\\\R(20)=(30+20)(7000-100\cdot20)\\\\R(20)=50\cdot5000\\\\R(20)=250000

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3 years ago
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Delicious77 [7]

Answer:

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Step-by-step explanation:

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