66%, then 2/3, and lastly 0.67. 2/3 is repeating so it is more then 66% but less than 0.67
Lets write an equation for each guy's shots and score:
4A + 2B = 18
3A + 3B = 21
To solve we multiply the first equation by -3 and the second by 2:
-12A - 6B = -54
6A + 6B = 42
--------------------
-12A + 0 = -12
A = 1
to find B we substitute in the first equation:
<span>4A + 2B = 18
</span><span>4(1) + 2B = 18
</span><span>4 + 2B = 18
</span>2B = 14
B = 7
therefore there were given 7 points in an arrow in B
Answer:
Malcolm is showing evidence of gambler's fallacy.
This is the tendency to think previous results can affect future performance of an event that is fundamentally random.
Step-by-step explanation:
Since each round of the roulette-style game is independent of each other. The probability that 8 will come up at any time remains the same, equal to the probability of each number from 1 to 10 coming up. That it has not come up in the last 15 minutes does not increase or decrease the probability that it would come up afterwards.
Answer:
<em>t = 1.51</em>
Step-by-step explanation:
<u>Exponential Model</u>
The exponential model is often used to simulate the behavior of a magnitude that either grow or decay in proportion to the existing amount of that magnitude.
The model can be expressed as
In this case, Mo is the initial mass of the radioactive substance and k is a constant which value is positive if the mass is growing or negative if the mass is decaying.
The value of k is not precisely given in the question, we are assuming 
The model is now
We are required to compute the time it takes the mass to reach one-half of its initial value:
Simplifying
Taking logarithms
Solving for t
