Using the p-value method, the decision rule is:
- |z| < 1.645: do not reject the null hypothesis.
- |z| > 1.645: reject the null hypothesis.
<h3>What is the relation between the p-value and the test hypothesis?</h3>
Depends on if the p-value is less or more than the significance level:
- If it is more, the null hypothesis is not rejected.
- If it is less, it is rejected.
In this problem, we have a two-tailed test, as we are testing if the mean is different of a value. For a significance level of 0.1, the critical value of z(when a p-value of 0.1 is obtained) is of |z| = 1.645, hence the decision rule is:
- |z| < 1.645: do not reject the null hypothesis.
- |z| > 1.645: reject the null hypothesis.
More can be learned about p-values at brainly.com/question/13873630
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Answer:
2.55km
Step-by-step explanation:
where:
d=distance
s=speed
t=time
X = <span> least integer
x + 2 = </span><span>middle integer
x + 4 = </span><span>greatest integer
x + x + 2 - (x + 4) = 3030
2x + 2 - x - 4 = 3030
x - 2 = 3030
x = 3030 + 2
x = 3032 </span>← least integer
middle integer = x + 2 = 3034
greatest integer = x + 4 = 3032 + 4 = 3036
Check:
3032 + 3034 = 6066
3036 + 3030 = 6066
6066 = 6066
Answer:
a. Point S
b. Line segment PT and Line segment ST
c. PSQRU
d. Lines PR and SQ
e. Plane C and Plane QRS
Step-by-step explanation:
Answer:
(a) Mean = 36.05; (b) median = 37; (c) mode = 37
Step-by-step explanation:
I am assuming your DFT is like this:
(a) Mean
The mean is the sum of all the data points divided by the number of points. I have done some of the calculations for you in the table below
(b) Median
The median is the middle value in your list of observations.
Your data set contains 19 terms, so the middle is (19/2)th term.
Count down the column of cumulative frequency (cf) until cf = 9½.
The 9½th term is 37.
Median = 37
(c) Mode
The mode is the value that appears most often in your list of observations.
It is obvious from your table that the number that occurs most frequently is 37.
Mode = 37
The diagram below shows that the score of 37 is predominant.