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ehidna [41]
3 years ago
13

If Cody has 11 dimes and quarters in his pocket, and they have a combined value of 170 cents, how many of each coin does he have

?
Mathematics
1 answer:
postnew [5]3 years ago
5 0

Answer:

12 dimes and 2 quarters

Step-by-step explanation:

12 dimes is 120 cents and 2 quarters is 50 cents that perfectly gives us 170 cents. As worded if he has 11 Dimes and the rest is quarters and we want 170 cents then it's impossible. 11 dimes is going to be 110 cents plus 2 quarters is 160 cents or plus 3 quarters is going to be 185 cents. therefore you are either short or over the money.

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Answer:

a. \\ \mu = USD\;51.34; b. The 95% interval is USD [45.82, 56.86].

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The mean amount a customer spends at the grocery store

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The 95% confidence interval for the mean amount spent

For the 95% confidence interval for the mean, we have the value for the <em>mean = </em>51.34, as we have just found, the value for the<em> standard deviation</em> is already given as USD 20.00. There are 50 observations, so n = 50.

Moreover, for a 95% confidence, the value for the corresponding z-score is z = 1.96 (this is the confidence coefficient). Then, the formula for finding the "limits" values for the confidence interval is as follows:

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For the lower limit

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\\ 51.34 - 5.52

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Mathematically

\\ P(45.82 \leq \mu \leq 56.86) = 0.95

There is a probability of 0.95 that the values are between [45.82, 56.86], both inclusive.

We have to remember here that we are dealing with a sample. This sample has a standard deviation, called standard error of the sample, and is \\ \frac{20}{\sqrt{50}} \approx 2.83.

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We can see the graph below that represents the former.

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