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blagie [28]
3 years ago
10

Factor the expression below using the greatest common factor 6p3- 2p2 - 8p

Mathematics
1 answer:
miss Akunina [59]3 years ago
7 0

Answer:

The Factor of expression using the greatest common factor is 2p(3p^2- p-4)

Step-by-step explanation:

Consider the provide expression.

6p^3- 2p^2 - 8p

We need to Factor the expression using the greatest common factor.

First look at the coefficients of the variable.

The coefficients are the factor of 2.

Variable p is the greatest common factor in the provided expression.

2p\times 3p^2- 2p\times p- 2p\times 4

2p(3p^2- p-4)

Hence, the Factor of expression using the greatest common factor is 2p(3p^2- p-4).

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If k is parallel to l find the value of a and the value of b.
kipiarov [429]

Answer:

a = 30

b = 40

C

Step-by-step explanation:

This requires that you use a proportion.

a / (a + 15) = 40 / 60

The small triangle's sides are in proportion to the large triangles sides.

Reduce the right. Divide top and bottom by 20

a/(a + 15) = 40/20 // 60/20

a/(a + 15) = 2/3                    

Cross multiply

3a = 2(a + 15)            Remove the brackets on the right.

3a = 2a + 30

Subtract 2a from both sides

3a-2a = 30

a = 30

Find B

b is done exactly the same way.

b/(b+20) = 2/3

3b = 2b + 40

3b - 2b = 40

b = 40

3 0
3 years ago
Jayda is running around a track where 3 laps is 5km. She runs 6 laps in 20 min. What is her speed in min per km
zzz [600]

Answer:

2km/m

Step-by-step explanation:

6 laps = 10km

(because 3 x 2 = 6 and double 5km as well)

Distance divide time = speed

20 mins divided by 10km = 2km per minute

3 0
3 years ago
50 POINTS FOR THIS 1 QUESTION I JUST NEED THE ANSWER
Oksana_A [137]

Answer:

a = 3

b = 2

c = 0

d = -4

Step-by-step explanation:

Form 4 equations and solve simultaneously

28 = a(2)³ + b(2)² + c(2) + d

28 = 8a + 4b + 2c + d (1)

-5 = -a + b - c + d (2)

220 = 64a + 16b + 4c + d (3)

-20 = -8a + 4b - 2c + d (4)

(1) + (4)

28 = 8a + 4b + 2c + d

-20 = -8a + 4b - 2c + d

8 = 8b + 2d

d = 4 - 4b

Equation (2)

c = -a + b + d + 5

c = -a + b + 4 - 4b+ 5

c = -a - 3b + 9

28 = 8a + 4b + 2c + d (1)

28 = 8a + 4b + 2(-a - 3b + 9) + 4 - 4b

28 = 6a - 6b + 22

6a - 6b = 6

a - b = 1

a = b + 1

220 = 64a + 16b + 4c + d (3)

220 = 64(b + 1) + 16b + 4(-b - 1 - 3b + 9) + 4 - 4b

220 = 60b + 100

60b = 120

b = 2

a = 2 + 1

a = 3

c = -3 - 3(2) + 9

c = 0

d = 4 - 4(2)

d = -4

5 0
3 years ago
Read 2 more answers
A ratio compares the relative sizes of ______ quantities .​
Andre45 [30]

Answer:

two

Step-by-step explanation:

A ratio compares the relative sizes of two quantities .​

4 0
3 years ago
Please help me with #2! Thanks!!!
Tanya [424]
The answer is B because the inverse of a squared number is the square root.
7 0
3 years ago
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