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aivan3 [116]
2 years ago
13

Please help, will mark branliest and 33 points!

Mathematics
1 answer:
LuckyWell [14K]2 years ago
4 0

Answer:

Area  = 45 sq ft

Step-by-step explanation:

Scale conversion:

2 inches = 6 feet

5 inches = 15 feet

Area = 1/2 base times height

Area  - 1/2 x 6 x 15

Area = 45 ft squared

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Mrs. Davis bought 6 pounds of grapes for $18. At this rate, how much would 72 ounces of grapes have cost?
Sergio [31]

Answer:

Step-by-step explanation:

1 pound = 16 ounce

6 pound = 6 * 16 = 96 ounces

Cost of 96 ounces of grapes = $18

Cost of 1 ounce of grape = 18/96

Cost of 72 ounces of grape = 18*72 / 96 = 27/2

                                              = $13.50

Or

Direct Proportion because is weight increase, the cost will increase

96:18 = 72 : x

Product of means = Product of extremes

18*72 = x*96

18*72/96 = x

x =$13.50

8 0
3 years ago
Read 2 more answers
Write at least four rational numbers between -2/5 and -1/3.​
castortr0y [4]
Answer: -3/5, -1/2, -7/12, -6/11
7 0
2 years ago
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On a coordinate plane, A line is drawn from point Fernando to point Maria. Fountain is labeled in between the 2. Fernando is at
agasfer [191]

The location of the fountain as described in the task content is; (-1, -0.5).

<h3>What is the location of the Fountain?</h3>

According to the task content, the locations of Fernando and Maria are given as; (-4, -2) and (4,2) respectively and the ratio of division is expected to be; 5: 3.

Hence, the coordinates of the fountain can be evaluated as;

x = (4) - (4-(-4)) × (5/8) = -1.

y = 2 - (2-(-2)) × (5/8) = -0.5

Hence, it follows that the coordinates of the fountain location is; (-1, -0.5) since the fountain is closer to Fernando than Maria.

Read more on dividing lines by ratios;

brainly.com/question/21108138

#SPJ1

8 0
1 year ago
Angle 2 and angle 3 are _______ angles? Need help ASAP​
Debora [2.8K]
Supplementary angles
4 0
3 years ago
Evaluate the triple integral_E x^6e^y dV where E is bounded by the parabolic cylinder z = 25 - y^2 and the planes z = 0, x = 5,
Nimfa-mama [501]

Nothing crazy here, just a matter of figuring out the limits of integration.

\displaystyle\iiint_Ex^6e^y\,\mathrm dV=\int_{-5}^5\int_{-5}^5\int_0^{25-y^2}x^6e^y\,\mathrm dz\,\mathrm dy\,\mathrm dx

=\displaystyle\int_{-5}^{-5}\int_{-5}^5x^6e^y(25-y^2)\,\mathrm dy\,\mathrm dx

=\displaystyle\left(\int_{-5}^5x^6\,\mathrm dx\right)\left(\int_{-5}^5e^y(25-y^2)\,\mathrm dy\right)=\boxed{\frac{625,000(3+2e^{10})}{7e^5}}

4 0
3 years ago
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