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stich3 [128]
2 years ago
12

The tallest tree in the world is 379 feet tall. How tall will each of the trees be in the year 2030 if their models continue? Is

this reasonable for each tree?.
Mathematics
1 answer:
tresset_1 [31]2 years ago
3 0

Models are patterns that are used to predict measurements and populations

<h3>How to model the tree</h3>

The question is incomplete, as the model and the dataset to model that growth of the tree are not given.

So, I will give a general explanation

If the model of the tree follows a linear model (e.g y = 2x + 3), then the model is not reasonable.

This is so because, population and growth cannot be measured by a linear model

However, if the growth of the trees follow an exponential model (e.g y = 2(3)^x), then the model is reasonable

Read more about mathematical models at:

brainly.com/question/24282972

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Answer:

z=\frac{12.95-12}{\frac{3}{\sqrt{36}}}=1.9  

p_v =P(z>1.9)=0.0287  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 12 at 5% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=12.95 represent the sample mean

\sigma=3 represent the population standard deviation for the sample  

n=36 sample size  

\mu_o =12 represent the value that we want to test  

\alpha=0.05 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is equal to 12, the system of hypothesis would be:  

Null hypothesis:\mu \leq 12  

Alternative hypothesis:\mu > 12  

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

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z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

z=\frac{12.95-12}{\frac{3}{\sqrt{36}}}=1.9  

P-value  

Since is a right tailed test the p value would be:  

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If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 12 at 5% of signficance.  

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