Answer: The system we need to use is:
A = T - 3
A = (2/3)*T
Solving this, we get:
In a bag, there are 9 tangerines and 6 apples.
Step-by-step explanation:
The question seems to be incomplete, by a quick online search i've found the complete question:
"A fruit stand sells bags of apples and tangerines. • Each bag has 3 fewer apples than tangerines. 2 • In each bag, the number of apples is 2/3 the number of tangerines..."
We know that:
A = number of apples in one bag
T = number of tangerines in one bag
We also know that:
"Each bag has 3 fewer apples than tangerines"
This can be written as:
A = T - 3
"In each bag, the number of apples is 2/3 the number of tangerines"
This can be written as:
A = (2/3)*T
Then we have a system of equations:
A = T - 3
A = (2/3)*T
This is the system of equations that can be used to solve for A and T, now let's solve this.
Because A means the same thing in both equations, then we can write:
A = T - 3 = A = (2/3)*T
Then:
T - 3 = (2/3)*T
We can solve this for T.
T - 3 = (2/3)*T
T - (2/3)*T = 3
(1 - 2/3)*T = 3
(1/3)*T = 3
T = 3/(1/3) = 3*3 = 9
This means that in each bag we have 9 tangerines in a bag.
Now we can use any of the two equations in the system to find the value of A.
I will use the first one:
A = T - 3
Now let's replace T by 9, then:
A = 9 - 3 = 6
A = 6
So there are 6 apples in a bag.
