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Lostsunrise [7]
3 years ago
11

Write the number in standard and expanded form. 304,800,400

Mathematics
1 answer:
Alja [10]3 years ago
4 0

We have to express the number 304,800,400 in standard and expanded form.

The expanded form is shown as a sum of each digit multiplied by its matching place value. Let us express the number in expanded from.

So, 304,800,400 = (3 \times 100000000) + (4 \times 1000000) + (8 \times 100000)+ (4 \times 100)

= 300000000 + 4000000 + 800000+400

So, this is the expanded form of the given number.

Standard form is a way of writing down very large or very small numbers easily.

The standard from of the number is:

304,800,400 = 3.048004 \times 10^8.

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ABCD is a parallelogram.<br>Angle CDA is 56°<br>What is the measure of angle ABC?​
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Answer:

Step-by-step explanation:

angle CDA = angle ABC (opposite angles of a parallelogram are equal)

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therefore angle ABC is 56 degree.

6 0
3 years ago
GEOMETRY-TRIG
Andrej [43]

Answer:

6. The distance Rampy Ronald would have travelled horizontally is approximately 48.428 feet for an actual maximum height of 21.486 feet

7. Rampy Ronald is going to make the jump

Please find attached the graph of the motion of Rampy Ronald, created with Microsoft Excel

Step-by-step explanation:

6. The given parameters are;

The width of the ravine = 80 ft

The inclination of the ramp with which Rampy Ronald will jump = 30°

The distance from the edge of the ravine the ramp ends = 5 feet

The speed with which Rampy Ronald will make the jump = 60 mph

The maximum height he will reach = 30 feet

Therefore, we have;

The height of the end of the ramp = 15 × sin(30°) = 7.5

The height of the end of the ramp = 7.5 feet

The height of the jump = 30 - 7.5 = 22.5

The vertical velocity = 60 × sin(30°) = 30

The vertical velocity = 30 mph

The horizontal velocity = 60 × cos(30°) = 30·√3

The horizontal velocity = 30·√3 mph

From the kinematic equation, v² = u² - 2gh, we have;

u² = 2gh

h = u²/2g = 900/(2 × 32.17405) ≈ 13.986

The maximum height reached 13.986 + 7.5 = 21.486

From v = u - gt

t = u/g = 30/32.17405 ≈ 0.932

t  ≈ 0.932 s

The distance Rampy Ronald would have travelled horizontally = 30·√3 × 0.932 ≈ 48.428

The distance Rampy Ronald would have travelled horizontally ≈ 48.428 feet

7. The time before Rampy Ronald reaches ground level again, is given by the following relation;

h = 1/2·g·t²

21.846 = 1/2 × 32.17405 × t²

t = √(21.846/16.087025) ≈ 1.165

t ≈ 1.366 s

The horizontal distance traveled is therefore;

The horizontal distance traveled from maximum height is 30·√3 × 1.165 ≈ 60.535

The horizontal distance traveled from maximum height is ≈ 70.979 feet

The total horizontal distance traveled ≈ 48.428 + 60.535 = 108.963

The total horizontal distance traveled ≈ 108.963 feet

The total horizontal distance required to make it across the ravine = 5 feet + 80 feet = 85 feet

Therefore, Rampy Ronald is going to make the jump

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