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3 years ago

Write the number in standard and expanded form. 304,800,400

Mathematics

1 answer:

Alja [10]3 years ago

4 0

We have to express the number 304,800,400 in standard and expanded form.

The expanded form is shown as a sum of each digit multiplied by its matching place value. Let us express the number in expanded from.

So, 304,800,400 = $(3 \times 100000000) + (4 \times 1000000) + (8 \times 100000)+ (4 \times 100)$

= $300000000 + 4000000 + 800000+400$

So, this is the expanded form of the given number.

Standard form is a way of writing down very large or very small numbers easily.

The standard from of the number is:

304,800,400 = $3.048004 \times 10^8$ .

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katrin2010 [14]

Answer:

2 7/12

Step-by-step explanation:

Make 4 1/4 and 1 2/3 have a common denominator.

4 1/4 - 1 2/3 = 31/12

31/12 simplified is 2 7/12

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3 years ago

last week, todd started a new job. he worked 35 hours over 5 workdays of equal length. he makes $9 an hour. how much did todd ma

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Answer:

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Step-by-step explanation:

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3 years ago

(1 + 2/3)*(1+2/5)*(1+2/7)*(1+2/9)

strojnjashka [21]

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Step-by-step explanation:

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3 years ago

It takes the high-speed train x hours to travel the z miles from Town A to Town B at a constant rate, while it takes the regular

e-lub [12.9K]

Answer:

$\Delta d =\frac{y-x}{y}*d_{Hs}\$

Step-by-step explanation:

Fist the velocity of high-speed train will be given by:

$V_{Hs} =\frac{z}{x}$

And the velocity of the regular will be given by:

$V_{R} =\frac{z}{y}$

The position equations of each movement will be given by:

$d_{Hs} =\frac{z}{x} t$

$d_{R} =z-\frac{z}{y} t$

We can get the encounter point isolating t in the first equation and reepalcing it in the second one:

First isolating:

$d_{Hs}\frac{x}{z} = t$

Second reeplacing t:

$d_{R} =z-\frac{z}{y}*d_{Hs}\frac{x}{z}$

$d_{R}=z-\frac{x}{y}*d_{Hs}\$

In the moment of the encounter the high-speed train have gone round $d_{Hs}\$ and the regular one $\frac{x}{y}*d_{Hs}\$

Then the difference between the distance traveled the high-speed train and the regular one is:

$\Delta d =d_{Hs}-\frac{x}{y}*d_{Hs}\$

$\Delta d =\frac{y-x}{y}*d_{Hs}\$

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4 years ago

An engineering school reports that 57% of its students were male (M), 33% of its students were between the ages of 18 and 20 (A)

aleksandrvk [35]

Answer: See explanation

Step-by-step explanation:

A table has been attached for further information.

The probability of a random student being male or between the ages of 18 and 20 will be:

= P(male)+P(18-20 age) - P(male and 18-20 age)

= 0.57 + 0.33 - 0.20

= 0.70

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3 years ago