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Strike441 [17]
3 years ago
9

phillip watched a beach volleyball game from 1:45 pm to 2:00pm how many degrees did the minute hand turn?

Mathematics
1 answer:
Iteru [2.4K]3 years ago
6 0
The answer is 15 or 1/4

I hope this helps you
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The surface area of the solid is about ____ inches squared
Dafna11 [192]

Answer:

Surface area of the whole figure=  320.28inch^2

Step-by-step explanation:

The surface area of the figure :

Surface area of the cylinder(excluding top)+Surface area of the cone(excluding bottom)

Radius of the cylinder=3 inch     and  Height of cylinder=13 inch

Surface area of the cylinder with one circular face

                                    =2\pi rh+\pi r^2

As,     \pi =\frac{22}{7}= 3.14

   =(2*3.14*3*13)+(3.14*3*3)\\\\=244.92+28.26\\\\=273.18inch^2

Surface area of the cone excluding  base:

                =\pi *r*l

l= slant height=5 inch       r= radius= 3 inch

Surface area of the cone =3.14*3*5

                                        =47.1inch^2

Total surface area of the whole figure=273.18+47.1

                                                           =  320.28inch^2

5 0
3 years ago
Maths<br> Share £72 in the ratio 2:7
avanturin [10]
2+7= 9 
72 / 9 = 8
8 * 2 = 16
<span>8 * 7 = 56 
</span>16:56
<span>
Key: 
</span>* = times
<span>/ = divide</span>
5 0
3 years ago
What is the area of this triangle?
Nikolay [14]

Answer:13.1

Step-by-step explanation:

Area equation:S=S=\frac{1}{2} ab sinθ

4 0
2 years ago
Lesson: 1.08Given this function: f(x) = 4 cos(TTX) + 1Find the following and be sure to show work for period, maximum, and minim
Ber [7]

The given function is

f(x)=4\cos \text{(}\pi x)+1

The general form of the cosine function is

y=a\cos (bx+c)+d

a is the amplitude

2pi/b is the period

c is the phase shift

d is the vertical shift

By comparing the two functions

a = 4

b = pi

c = 0

d = 1

Then its period is

\begin{gathered} \text{Period}=\frac{2\pi}{\pi} \\ \text{Period}=2 \end{gathered}

The equation of the midline is

y_{ml}=\frac{y_{\max }+y_{\min }}{2}

Since the maximum is at the greatest value of cos, which is 1, then

\begin{gathered} y_{\max }=4(1)+1 \\ y_{\max }=5 \end{gathered}

Since the minimum is at the smallest value of cos, which is -1, then

\begin{gathered} y_{\min }=4(-1)+1 \\ y_{\min }=-4+1 \\ y_{\min }=-3 \end{gathered}

Then substitute them in the equation of the midline

\begin{gathered} y_{ml}=\frac{5+(-3)}{2} \\ y_{ml}=\frac{2}{2} \\ y_{ml}=1 \end{gathered}

The answers are:

Period = 2

Equation of the midline is y = 1

Maximum = 5

Minimum = -3

3 0
1 year ago
1 question geometry :) thanks if you help
Inessa05 [86]

Step-by-step explanation:

II will be the 90° clockwise rotation,

III will be the translation

IV will be the 180° rotation

V will be the 90° counter clockwise rotation

3 0
3 years ago
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