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8090 [49]
2 years ago
11

The vector ab has a magnitude of 20 units and is parallel to the vector 4i + 3j. find ab.

Mathematics
1 answer:
stepladder [879]2 years ago
7 0

The vector ab has a magnitude of 20 units and is parallel to the

vector 4i + 3j. Hence, The vector AB is 16i + 12j.

<h3>How to find the vector?</h3>

If we have given a vector v of initial point A and terminal point B

v = ai + bj

then the components form as;

AB = xi + yj

Here, xi and yj are the components of the vector.

Given;

The vector ab has a magnitude of 20 units and is parallel to the

vector 4i + 3j.

magnitude

\sqrt{4^2 + 3^2} \\\\\sqrt{16 + 9} \\\\= 5

Unit vector in direction of resultant = (4i + 3j) / 5

Vector of magnitude 20 unit in direction of the resultant

= 20  x (4i + 3j) / 5

= 4 x (4i + 3j)

= 16i + 12j

Hence, The vector AB is 16i + 12j.

Learn more about vectors;

brainly.com/question/12500691

#SPJ1

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Angela bought a bookmark in the shape of an arrow as shown below. The base and height of the triangle are both 3 inches.
Lina20 [59]

The area of a 2D form is the amount of space within its perimeter. The area of the arrow is 11.25 in².

<h3>What is an area?</h3>

The area of a 2D form is the amount of space within its perimeter. It is measured in square units such as cm2, m2, and so on. To find the area of a square formula or another quadrilateral, multiply its length by its width.

For the given problem, the image is given below.

The area of the arrow is,

Area =  Area of rectangle + Area of triangle

        = (1.5 in × 4.5 in) + (0.5×3×3)

        = 6.75 in² + 4.5 in²

        = 11.25 in²

Hence, the area of the arrow is 11.25 in².

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7 0
2 years ago
Describe youre version of a best freind
Alecsey [184]

Answer:

To me is a best freind is someone who has my back no matter what.

Step-by-step explanation:

3 0
3 years ago
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In an expression<br>(8/9) squared (-81)+3/5dividedby-9/10
Nitella [24]
If you wanted to calculate it, there it is:
(\frac{8}{9})^2 (-81)+\frac{\frac{3}{5}}{\frac{-9}{10}} = \frac{64}{81}*(-81)+\frac{3}{5}*\frac{10}{-9} = -64+\frac{-2}{3}= \\ =-64-\frac{2}{3}=\frac{-192-2}{3}=\frac{-194}{3}
6 0
3 years ago
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The Colonel spots a campfire at a bearing N 59∘59∘ E from his current position. Sarge, who is positioned 242 feet due east of th
Rashid [163]

Answer:

i. Colonel is about 201 feet away from the fire.

ii. Sarge is about 125 feet away from the fire.

Step-by-step explanation:

Let the Colonel's location be represented by A, the Sarge's by B and that of campfire by C.

The total angle at the campfire from both the Colonel and Sarge = 59^{0} + 34^{0}

                                           = 93^{0}

Thus,

<CAB = 90^{0} - 59^{0} = 31^{0}

<CBA = 90^{0} - 34^{0} = 56^{0}

Sine rule states;

\frac{a}{Sin A} = \frac{b}{Sin B} = \frac{c}{Sin C}

i. Colonel's distance from the campfire (b), can be determined by applying the sine rule;

\frac{b}{Sin B} = \frac{c}{Sin C}

\frac{b}{Sin 56^{0} } = \frac{242}{Sin 93^{0} }

\frac{b}{0.8290} = \frac{242}{0.9986}

cross multiply,

b = \frac{0.8290*242}{0.9986}

  = 200.8993

Colonel is about 201 feet away from the fire.

ii. Sarge's distance from the campfire (a), can be determined by applying the sine rule;

\frac{a}{Sin A} = \frac{c}{Sin C}

\frac{a}{Sin 31^{0} } = \frac{242}{Sin 93^{0} }

\frac{a}{0.5150} = \frac{242}{0.9986}

cross multiply,

a = \frac{0.5150*242}{0.9986}

  = 124.8073

Sarge is about 125 feet away from the fire.

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Writing a linear equations
Ket [755]
Answer:
-1/7
Hope that helped
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