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zepelin [54]
2 years ago
11

A supervisor finds the mean number of miles that the employees in a department live from work. he finds x overbar = 29 and s = 3

.6. which mileage is within a z-score of 1.5? 21 miles 24 miles 36 miles 41 miles
Mathematics
2 answers:
V125BC [204]2 years ago
7 0

A supervisor finds the mean number of miles that the employees in a department live from work is 24. Then the correct option is B.

<h3>What is a z-score?</h3>

The z-score is a numerical measurement used in statistics of the value's relationship to the mean of a group of values, measured in terms of standards from the mean.

The z-score is given as

z = \dfrac{x-\mu }{s}\\

x = 29

s = 3.6

z = 1.5

Then the mean will be

1.5 = \dfrac{29 - \mu }{3.6}\\\\\mu = 29 - 5.4\\\\\mu = 23.6 \approx 24

More about the z-score link is given below.

brainly.com/question/15016913

Iteru [2.4K]2 years ago
4 0

Answer:

B) 24 miles

Step-by-step explanation:

100% edge 2022

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AleksandrR [38]

Answer:

Step-by-step explanation:

Let t = flying time in seconds for each plane

Descending rate = 40 ft/s

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Descending height, hd= 19200 - 40t

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Equating hd = ha, therefore:

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3 years ago
10% of the downtown residents of a town in the Plains live in mobile homes. Based on data from past tornadoes, if a tornado goes
tia_tia [17]

Answer:

The probability a person will not live in a mobile home if they do not die as a result of the tornado is 0.9265.

Step-by-step explanation:

Denote the events as follows:

<em>X</em> = a person lives in a mobile home.

<em>Y</em> = a person dies as a result of tornado.

Given:

P(X)=0.10\\P(Y|X) = 0.30\\P(Y|X^{c})=0.02\\

Compute the value of P(Y^{c}|X^{c}) as follows:

P(Y^{c}|X^{c})=1-P(Y|X^{c})\\=1-0.02\\=0.98

Compute the probability that a person dies as a result of tornado as follows:

P(Y)=P(Y|X)P(X)+P(Y|X^{c})P(X^{c})\\=(0.30\times0.10)+(0.02\times(1-0.10))\\=0.03+0.018\\=0.048

Then the probability that a person does not dies as a result of tornado is:

P(Y^{c})=1-P(Y)\\=1-0.048\\=0.952

Compute the value of P(X^{c}|Y^{c}) as follows:

P(X^{c}|Y^{c})=\frac{P(Y^{c}|X^{c})P(X^{c})}{P(Y^{c})}=\frac{0.98\times(1-0.10)}{0.952}=0.9265

Thus, the probability a person will not live in a mobile home if they do not die as a result of the tornado is 0.9265.

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Answer:

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