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gulaghasi [49]
3 years ago
12

He histogram shows the finishing times of runners in a race.

Mathematics
1 answer:
kobusy [5.1K]3 years ago
4 0
11 runners took at least 30 minutes to finish the race. (:
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Tay–Sachs Disease Tay–Sachs disease is a genetic disorder that is usually fatal in young children. If both parents are carri
BARSIC [14]

Answer:

a) 0.0156 = 1.56% probability that all children will develop the disease.

b) 0.4219 = 42.19% probability that only one child will develop the disease.

c) 0.1406 = 14.06% probability that the third children will develop the disease, given that the first two did not.

Step-by-step explanation:

For each children, there are only two possible outcomes. Either they carry the disease, or they do not. The probability of a children carrying the disease is independent of any other children, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The probability that their offspring will develop the disease is approximately .25.

This means that p = 0.25

Three children:

This means that n = 3

Question a:

This is P(X = 3). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 3) = C_{3,3}.(0.25)^{3}.(0.75)^{0} = 0.0156

0.0156 = 1.56% probability that all children will develop the disease.

Question b:

This is P(X = 1). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{3,1}.(0.25)^{1}.(0.75)^{2} = 0.4219

0.4219 = 42.19% probability that only one child will develop the disease.

c. The third child will develop Tay–Sachs disease, given that the first two did not.

Third independent of the first two, so just multiply the probabilities.

First two do not develop, each with 0.75 probability.

Third develops, which 0.25 probability. So

p = 0.75*0.75*0.25 = 0.1406

0.1406 = 14.06% probability that the third children will develop the disease, given that the first two did not.

6 0
3 years ago
I need help with this question pls
Marrrta [24]

Answer:

yes

Step-by-step explanation:

yes it is because if 6ounces is $2.10 and the more ounces you add the higher the cost

btw just copy/paste :P

4 0
3 years ago
What is the range of f(x)=15(1/3)^x
wel

Answer:

(0,inf)   {y║y>0}

Step-by-step explanation:

8 0
3 years ago
Given the points (3, 2) and (6, 4), which of the following are true about the line passing through these points?
Artist 52 [7]
I don't know what 'which of the following' is referring to, but the line has a positive slope, goes through the origin, and has a slope of 2/3.
5 0
3 years ago
Read 2 more answers
Please help me really quick! :DD
shutvik [7]

Answer:

Correct equation: 4b^2 -b-138= 0

Solution: 6 meters

Step-by-step explanation:

The base has to be 6, and that’s the equation that works with that number.

8 0
2 years ago
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