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aalyn [17]
3 years ago
13

A high school is having a talent contest and will give different prizes for the best 5 acts in the show. First place wins the mo

st money, and each place after that wins $50 less than the previous place. Part A Create a model that can be used to determine the total amount of prize money based on the value of the first place prize Enter your model in the box provided. ​
Mathematics
1 answer:
horsena [70]3 years ago
5 0

The model that can be used to determine the total amount of prize money based on the value of the first place prize is as follows;

Total amount of price money = 5x - 500

The prices are given to the best 5 acts. The first place wins the most money and each place after that wins $50 less than the previous place. The pattern follows a sequence.

<h3>What is a Sequence?</h3>

Sequence  is a list of things (usually numbers) that are in order. Therefore,

let

the first price = x

The common difference of the sequence would be - 50.

To create a model that can be used to determine the total amount of prize money based on the value of the first place prize can be done as follows;

  • x , x - 50, x - 100, x - 150, x - 200

Therefore,

Total amount of price money = x + x - 50 + x - 100 + x - 150 +  x - 200

Total amount of price money = 5x - 500

learn more on model here: brainly.com/question/2400667

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Answer:

x < -5  or  x = 1  or  2 < x < 3  or  x > 3

Step-by-step explanation:

Given <u>rational inequality</u>:

\dfrac{(x-1)^2(x-2)^3}{(x^2-5x+6)^2(x+5)}\geq 0

\textsf{Factor }(x^2-5x+6):

\implies x^2-2x-3x+6

\implies x(x-2)-3(x-2)

\implies (x-3)(x-2)

Therefore:

\dfrac{(x-1)^2(x-2)^3}{(x-3)^2(x-2)^2(x+5)}\geq 0

Find the roots by solving f(x) = 0  (set the numerator to zero):

\implies (x-1)^2(x-2)^3=0

\implies (x-1)^2=0\implies x=1

\implies (x-2)^3=0 \implies x=2

Find the restrictions by solving f(x) = <em>undefined  </em>(set the denominator to zero):

\implies (x-3)^2(x-2)^2(x+5)=0

\implies (x-3)^2=0 \implies x=3

\implies (x-2)^2=0 \implies x=2

\implies (x+5)=0 \implies x=-5

Create a sign chart, using closed dots for the <u>roots</u> and open dots for the <u>restrictions</u> (see attached).

Choose a test value for each region, including one to the left of all the critical values and one to the right of all the critical values.

Test values:  -6, 0, 1.5, 2.5, 4

For each test value, determine if the function is positive or negative:

f(-6)=\dfrac{(-6-1)^2(-6-2)^3}{(-6-3)^2(-6-2)^2(-6+5)}=\dfrac{(+)(-)}{(+)(+)(-)}=+

f(0)=\dfrac{(0-1)^2(0-2)^3}{(0-3)^2(0-2)^2(0+5)}=\dfrac{(+)(-)}{(+)(+)(+)}=-

f(1.5)=\dfrac{(1.5-1)^2(1.5-2)^3}{(1.5-3)^2(1.5-2)^2(1.5+5)}=\dfrac{(+)(-)}{(+)(+)(+)}=-

f(2.5)=\dfrac{(2.5-1)^2(2.5-2)^3}{(2.5-3)^2(2.5-2)^2(2.5+5)}=\dfrac{(+)(+)}{(+)(+)(+)}=+

f(4)=\dfrac{(4-1)^2(4-2)^3}{(4-3)^2(4-2)^2(4+5)}=\dfrac{(+)(+)}{(+)(+)(+)}=+

Record the results on the sign chart for each region (see attached).

As we need to find the values for which f(x) ≥ 0, shade the appropriate regions (zero or positive) on the sign chart (see attached).

Therefore, the solution set is:

x < -5  or  x = 1  or  2 < x < 3  or  x > 3

As interval notation:

(- \infty,-5) \cup x=1 \cup (2,3) \cup(3,\infty)

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Answer:

The answer to your question is:

12) C

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Step-by-step explanation:

12)

Data

A (6, -3)

B (-6, 19)

midx = (x1 + x2) / 2                            midy = (y1 ´y2) / 2

midx = ( 6 - 6) / 2                               midy = (-3 + 19) / 2

midx = 0 / 2                                      midy = 16 / 2

midx = 0                                            midy = 8

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13)

As A is the midpoint of CT then CA = AT

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                AT = 29

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