I would say you cannot use a rectangle. Or a circle. One of those.
Answer:
New can holds
more than the old can
Step-by-step explanation:
Given: Diameter of the can is 6 cm and height is 12 cm such that volume of can is 
Dimensions of the can are increased by a multiple of 1.10
To find: Difference between the volume of new can and volume of old can
Solution:
Volume of can (v) = 
Let r, h denote radius and height of the can.
Let R, H denotes radius and height of the new can.
r = diameter/2 = 
h = 12 cm
R = 
H = 
New volume (V) = 
So,

Answer:
for the first one the answer is D :)
Step-by-step explanation:
Answer:
Average Rate of Change : 3
Step-by-step explanation:
" Remember that the average rate of change of function f say, on interval [a,b] would be f(b) - f(a) / b - a. Similarly we can solve for the average rate of this function. "
f(5) = x² - 2x - 15 = 5² - 2(5) - 15 = 25 - 10 - 15 = 0,
f(0) = 0² - 2(0) - 15 = 0 - 0 - 15 = - 15
And the average rate of change will be,
f(5) - f(0) / 5 - 0 = 0 - ( - 15 ) / 5 - 0
= 0 + 15 / 5 = 15 / 5 = 3
The average rate of change over the interval [0, 5] is hence 3.