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AysviL [449]
3 years ago
9

Find the value of k so that the

Mathematics
1 answer:
BaLLatris [955]3 years ago
8 0

Answer:

gradient =  - 3 \\  - 3 =  \frac{(8 + 1)}{( - 2 - k)}  \\  3(2 + k) = 9 \\ 2 + k = 3 \\ k = 1

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How can I solve this proof?? PLZ HELP I DONT UNDERSTAND!! Thanks !!
love history [14]

Hello from MrBillDoesMath!

Answer:

See below


Discussion:

Triangles BAD and BCD are congruent by the SAS postulate.

          * Side AD = DC because BD is the perpendicular bisector  of AC.

          * Angle ADB and CDB are both right angles, and hence equal, because

            BD is the perpendicular bisector of AC)


Corresponding parts of congruent triangles are equal so angle BAD = angle BCD,  which was to be proven.


Regards,  

MrB

8 0
3 years ago
2.0Plss solve for x...........................
Paul [167]

Answer:

x = - 7

Step-by-step explanation:

( x + 139 ) and 132 are vertically opposite angles.

Vertically opposite angles are equal,

x + 139 = 132

x = 132 - 139

x = - 7

7 0
3 years ago
I would like to know how to decrease 280 by 73%
trapecia [35]

Answer:

<em>75.6</em>

Step-by-step explanation:

100% - 73% = 27%  

27% = 0.27

280 × 0.27 = <em>75.6</em>

7 0
2 years ago
Find the value of SU
sineoko [7]

Answer:

A

Step-by-step explanation:

yw

3 0
3 years ago
12. Determine the area of the shaded region. 12 in 12 in​
vekshin1

Answer:

  • 216/7 in²

Step-by-step explanation:

<u>We know that:</u>

  • Area of shaded region = Area of square - Area of circles
  • Radius of circle = 3 in
  • Area of circle = πr²
  • Area of square = s²

<u>Solution:</u>

  • Area of shaded region = Area of square - Area of circles
  • => Area of shaded region = (12²) - 4(22/7 x 3 x 3)
  • => Area of shaded region = (144) - 4(22/7 x 9)
  • => Area of shaded region = (144) - 4(198/7)
  • => Area of shaded region = 144 - 792/7
  • => Area of shaded region = 144 x 7/7 - 792/7
  • => Area of shaded region = 1008/7 - 792/7
  • => Area of shaded region = 1008/7 - 792/7
  • => Area of shaded region = 216/7 in²
3 0
3 years ago
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