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Lapatulllka [165]
2 years ago
13

Solve for x, 3(x – 4) ≥ 5x + 2

Mathematics
1 answer:
Flauer [41]2 years ago
7 0

\Large\textsc{answer :}

x≤-7

\Large\textsc{calculations :}

First , use the distributive property :

3(x-4)≥5x+2

3x-12≥5x+2

Subtract 5x on both sides :

3x-5x-12≥2

Now , add 12 on both sides :

3x-5x≥2+12

3x-5x≥14

Subtract the x's :

-2x≥14

Divide by -2 on both sides and watch what happens :

x≤-7 (notice that the inequality sign changed from "greater than or equal to" to "less than or equal to")

If we divide both sides of an inequality by a negative number , we change the inequality sign .

\footnotesize\textit{hope helpful~}

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If y varies directly as​ x, and y=8 when x=3​, find y when x=15.
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y=40

Step-by-step explanation:

The formula for Direct Variation is y=kx or k=y/x. In this case I would use k=y/x. If you're y is 8 and x is 3, this means that K=8/3. Using this, we know that X=15. We have to find a Y value so that the fraction with an x of 15 simplified is 8/3. To do this you would write 8/3 and y/15. Now cross multiply to get 3y=120. Divide by 3 to get y=40. View my attachment for the work!

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