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lina2011 [118]
3 years ago
6

Evaluate the expression 4/15÷x+0.4 for x if: x=1, x=4/9, x=1 1/3. Solve for each X. I need help Will give brainliest!

Mathematics
1 answer:
AfilCa [17]3 years ago
8 0

Answer:

4/15 ÷ x + 0.4

When x = 1

4/15 ÷ 1 + 0.4

x = 2/3

When x = 4/9

4/15 ÷ 4/9 +0.4

x = 1

When x = 1 ⅓ = 4/3

4/15 ÷ 4/3 + 0.4

x = 3/5

Hope this helps.

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Answer:

\frac{y-x}{xy}

Step-by-step explanation:

y - x / xy

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Suppose that you have eight cards. Five are green and three are yellow. The five green cards are numbered 1, 2, 3, 4, and 5. The
Marina86 [1]

Answer:

Step-by-step explanation:

Given that you have eight cards. Five are green and three are yellow. The five green cards are numbered 1, 2, 3, 4, and 5. The three yellow cards are numbered 1, 2, and 3. The cards are well shuffled. You randomly draw one card.

G = card drawn is green

Y = card drawn is yellow

E = card drawn is even-numbered

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Sample space = {G1, G2, G3, G4, G5, Y1, Y2, Y3}

2) P(G) = 5/8

3) P(G/E) = P(GE)/P(E)

GE = {G2, G4}

Hence P(G/E) = 2/5

4) GE = {G2, G4}

P(GE) = 2/8 = 1/4

5) P(G or E) = P(G)+P(E)-P(GE)

= 5/8 + 3/8-2/8 = 3/5

6) No there is common element as G2 and G4

Cannot be mutually exclusive

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3 years ago
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Find the valuesof integers x and y: x^(8)+16y^(8)=0
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8 0
4 years ago
Se quiere construir un muro de 4 m de alto, 12 m de largo y 10 cm de espesor. ¿Cuántos ladrillos de 8 cm de alto, 20 cm de largo
Llana [10]

Answer:

3000

Step-by-step explanation:

Let's start by finding the volume of the wall. The volumen of the wall can be considered as the volume of a rectangular prism. The volume of a rectangular prism is given by:

V_w=w*l*h\\\\Where:\\\\w=Width=10cm=0.1m\\l=Length=12m\\h=Height=4m

So the volume of the wall is:

V_w=0.1*12*4=4.8m^3

Now, we can find the volume of the brick using the same method since a brick can be considered as a rectangular prism as well:

V_b=w*l*h\\\\For\hspace{3}the\hspace{3}brick\\\\w=10cm=0.1m\\l=20cm=0.2m\\h=8cm=0.08m

Hence:

V_b=(0.1)*(0.2)*(0.08)=0.0016m^3

In order to know how many bricks are required to build the wall, we just need to fill the wall volume with the number of bricks of this volume. So:

V_w=nV_b\\\\Where\\\\n=Number\hspace{3}of\hspace{3}bricks

Solving for n:

n=\frac{V_w}{V_b} =\frac{4.8}{0.0016} =3000

Therefore, we need 3000 bricks to build that wall.

Translation:

Comencemos por encontrar el volumen del muro. El volumen del muro puede considerarse como el volumen de un prisma rectangular. El volumen de un prisma rectangular viene dado por:

V_w=w*l*h\\\\Donde:\\\\w=Espesor=10cm=0.1m\\l=Largo=12m\\h=Alto=4m

Entonces el volumen del muro es:

V_w=0.1*12*4=4.8m^3

Ahora, podemos encontrar el volumen del ladrillo utilizando el mismo método, ya que un ladrillo también puede considerarse como un prisma rectangular:

V_b=w*l*h\\\\Para\hspace{3}el\hspace{3}ladrillo\\\\w=10cm=0.1m\\l=20cm=0.2m\\h=8cm=0.08m

Por lo tanto:

V_b=(0.1)*(0.2)*(0.08)=0.0016m^3

Para saber cuántos ladrillos se requieren para construir el muro, solo necesitamos llenar el volumen del muro con la cantidad de ladrillos de este volumen. Entonces:

V_w=nV_b\\\\Donde\\\\n=Numero\hspace{3}de\hspace{3}ladrillos

Resolviendo para n:

n=\frac{V_w}{V_b} =\frac{4.8}{0.0016} =3000

Por lo tanto, necesitamos 3000 ladrillos para construir ese muro.

4 0
4 years ago
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