The PTA sells school supply packs each year. If 60% of the 400 students purchase from the PTA, then how many school supply packs
1 answer:
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Given:
A train travels 288 km at a uniform speed.
If the speed has been 4 km per hour more it would have taken one hour less for the same journey.
To find:
The initial speed of the train.
Solution:
Let x km/h be the initial speed on the train.
New speed of train = (x+4) km/h
We know that,
Time taken by the train initially to cover 288 km is hours.
New time taken by the train to cover 288 km is hours.
It is given that If the speed has been 4 km per hour more it would have taken one hour less for the same journey.
Splitting the middle term, we get
We know that the speed cannot be negative. So, the only possible value of x is 32.
Therefore, the speed of the train is 32 km/h.
The initial value: 25, rate of change: -5 ⇒ answer C
Step-by-step explanation:
The table:
→ x : 1 : 3 : 5 : 7
→ y : 20 : 10 : 0 : -10
The linear relation between x and y is y = m x + b, where
- m is the rate of change
- b is the initial value
Let us use the table to find m and b
∵ , where
and are any two ordered pairs in the table
∵ = (1 , 20)
∵ = (3 , 10)
∴
∵ m is the rate of change
∴ The rate of change is -5
Substitute the value of m in the form of the linear relation
∴ y = -5 x + b
To find b substitute x and y in the equation by the coordinates of any points in the table, let us chose point (5 , 0)
∵ x = 5 and y = 0
∴ 0 = -5(5) + b
∴ 0 = -25 + b
- Add 25 to both sides
∴ 25 = b
∵ b represents the initial value
∴ The initial value is 25
The initial value: 25, rate of change: -5
Learn more:
You can learn more about the linear equation in brainly.com/question/4326955
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