Answer:
1st is correct
Step-by-step explanation:
Like charges repel each other.
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The initial statement is: QS = SU (1)
QR = TU (2)
We have to probe that: RS = ST
Take the expression (1): QS = SU
We multiply both sides by R (QS)R = (SU)R
But (QS)R = S(QR) Then: S(QR) = (SU)R (3)
From the expression (2): QR = TU. Then, substituting it in to expression (3):
S(TU) = (SU)R (4)
But S(TU) = (ST)U and (SU)R = (RS)U
Then, the expression (4) can be re-written as:
(ST)U = (RS)U
Eliminating U from both sides you have: (ST) = (RS) The proof is done.
If we had AB: BC: CD, we could easily have solved that problem. In order to combine these ratios, we need to have the same number for BC. We can create this number by finding LCM (Least Common Multiple) for 5 and 3, which is 15. Then, we can write ratios of AB:BC = 6:15 and BC:CD=15:20. Now, we can easily combine these ratios. AB:BC:CD = 6:15:20. Then, 6k+15k+20k = 82 and k=2 cm. And BC = 30 cm
Answer:
A
Step-by-step explanation:
Using the cosine ratio in the right triangle
cos X = 
= 
= 
, then
∠ X = 
( ) ≈ 44° ( to the nearest degree ) → A
Answer:
q¹²
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
- Exponential Rule [Powering]:
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
(q⁶)²
<u>Step 2: Simplify</u>
- Exponential Rule [Powering]: q⁶⁽²⁾
- [Exponents] Multiply: q¹²
