Answer:
w+d≥14
Step-by-step explanation:
Here is the full question
Morgan is working two summer jobs, washing cars and walking dogs. She must work no less than 14 hours altogether between both jobs in a given week. Write an inequality that would represent the possible values for the number of hours washing cars, w, and the number of hours walking dogs, d, that Morgan can work in a given week.
Morgan must not work less than 14 hours. This means that the least amount of hours she can work would be 14 hours. This would be represented by the greater to or equal to sign (≥)
So the time she would spend working = w+d≥14
2
Answer:
I think its 55.5
Step-by-step explanation
Sorry if I got it wrong for you
This is rationalising the denominator of an imaginary fraction. We want to remove all i's from the denominator.
To do this, we multiply the fraction by 1. However 1 can be expressed in an infinite number of ways. For example, 1 = 2/2 = 3/3 = 4n^2 / 4n^2 (assuming n is not zero!). Let's express 1 as the complex conjugate of the denominator, divided by the complex conjugate of the denominator.
The complex conjugate of (3 - 2i) is (3 + 2i). Then do what I just said:
4/(3-2i) * (3+2i)/(3+2i) = 4(3+2i)/(3-2i)(3+2i) = (12+8i)/(9-4i^2) = (12+8i)/(9+4) = (12+8i)/13
This is the answer you are looking for. I hope this helps :)
Answer:
x=4
Step-by-step explanation:
Consider ΔKLJ:
sinθ=opposite/hypotenuse
sin30=LJ/8√2
LJ=0.5*8√2=4√2
Consider ΔMLJ:
sinθ=opp/hyp
sin45=x/4√2
1/√2=x/4√2
4√2/√2=x
x=4
Answer: I would love to help you but I am confused on what you mean by the question.
Step-by-step explanation:
