Answer:
b
Step-by-step explanation:
it's the only one were you can multiply and get the first number and the second number a multiple of the ratio 9:5
Answer:

Step-by-step explanation:
We need to use the properties shown below to solve this:
1. ![\sqrt[n]{x^a} =x^{\frac{a}{n}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%5Ea%7D%20%3Dx%5E%7B%5Cfrac%7Ba%7D%7Bn%7D%7D)
2. 
3. 
Area of a triangle is given by 1/2 * base * height, so we do that and simplify:

Quadrant number II
The quadrant II has the negative x axis and the positive y axis
It would be rounded to 20.
hope this helps you
1)
|-6-2|=|-8|=8
2)
G and I
3)
|-6+2|= |-4|=4
the point that is 4 units away from H and K is I
I=-2