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alex41 [277]
3 years ago
8

Write an equation for the line parallel to the line −4x−8=0 through the point (0,−9)

Mathematics
1 answer:
siniylev [52]3 years ago
3 0

Answer:

4y= -x - 28

Step-by-step explanation:

the products of the gradient of parallel lines is 1

m1 x m2=1.......(1)

8-4x=0

re-arranging we have

0=-4x +8

comparing with y=mx +c we have

m1=-4

put the value of m1 in eqn 1

-4 xm2 =1

m2 =-1\2

from the relation.....

m=y-y1\x-x1

put the value of m1 above

-1\2=y-(-9)\x-0

cross multiply

-1(x-8)=4(y+9)

-x +8=4y+36

re-arranging we have

4y=-x-36+8

4y=-x-28//

pls do ensure u tag me as brainliest

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Answer:

Complete Question:

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Step-by-step explanation:

TASK 3

The city picked is Baltimore, the year 2017.

The table is attached in picture #1.

a) The box-and-whisker plot is attached in picture #2.

b) The median is the central value of the distribution i.e:  

42.4, 45.3, 46.8 | 54.7, 57.6, 66.0 | 69.1,  76.5,  80.6 | 85.8, 87.8, 90.0 

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As we have 12 values,  the average between the two central values will be the median :

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Indeed, this value represents the first quartile. Similarly to point c), the position can be found by the formula:

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q₀.₂₅ = (46.8 + 54.7) / 2 = 50.8 °F. 

e) Baltimore in 2017 had a median high temperature of 67.1 °F.

25% of the year the high temperatures were warmer than 83.2 °F, with no outlier above 90.0 °F which was the hottest temperature.

25% of the high temperatures were colder than 50.8 °F, with no outlier below 42.4 °F, which was the coldest high temperature.

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Answer:

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The standard deviation of the number of errors missed is 1.4491.

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For each typing error, there are only two possible outcomes. Either it is caught, or it is not. The probability of a typing error being caught is independent of other errors. So we use the binomial probability distribution to solve this question.

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The standard deviation of the binomial distribution is:

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The mean number of errors missed is 3.

(c) What is the standard deviation of the number of errors caught?

\sqrt{V(Y)} = \sqrt{np(1-p)} = \sqrt{10*0.7*0.3} = 1.4491

The standard deviation of the number of errors caught is 1.4491.

What is the standard deviation of the number of errors missed?

\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{10*0.3*0.7} = 1.4491

The standard deviation of the number of errors missed is 1.4491.

6 0
3 years ago
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