Write an equation for the line parallel to the line −4x−8=0 through the point (0,−9)
1 answer:
Answer:
4y= -x - 28
Step-by-step explanation:
the products of the gradient of parallel lines is 1
m1 x m2=1.......(1)
8-4x=0
re-arranging we have
0=-4x +8
comparing with y=mx +c we have
m1=-4
put the value of m1 in eqn 1
-4 xm2 =1
m2 =-1\2
from the relation.....
m=y-y1\x-x1
put the value of m1 above
-1\2=y-(-9)\x-0
cross multiply
-1(x-8)=4(y+9)
-x +8=4y+36
re-arranging we have
4y=-x-36+8
4y=-x-28//
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