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Yuki888 [10]
3 years ago
12

Please help me figure this out!!!!!!

Mathematics
2 answers:
Firdavs [7]3 years ago
8 0
The answer is 129.13 is your answer. Remember, t<span>he perimeter of the base is 4s since it is a square. There is no formula for a </span>surface area<span> of a non-regular </span>pyramid<span> since slant height is not defined. To </span>find<span> the </span>area<span>, </span>find<span> the </span>area<span> of each face and the </span>area<span> of the base and add them.</span>
Sauron [17]3 years ago
8 0
Total surface area of pyramid = area of base + area of 4 triangular faces

area of base = 6.4*6.4 = 40.96 cm²
area of one triangular face = 1/2 * 6.4 * 6.1 = 19.52 cm²

Surface area of pyramid = 40.96 + 4 * 19.52 = 119.04 cm²
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The top and bottom horizontal sides are parallel, so this is a trapezoid with bases DC and AB. The height is BC.

area of trapezoid = (a + b)h/2

where a and b are the lengths of the bases, and h is the height.

We need to find the height, BC.

Drop a perpendicular from point A to segment DC. Call the point of intersection E. E is a point on segment DC.

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DE + 360 m = 600 m

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Use right triangle ADE to find AE. Then BC = AE.

DE² + AE² = AD²

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DE = 70

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area = (a + b)h/2

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