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3 years ago

Please help me figure this out!!!!!!

Mathematics

2 answers:

Firdavs [7]3 years ago

8 0

The answer is 129.13 is your answer. Remember, the perimeter of the base is 4s since it is a square. There is no formula for a surface area of a non-regular pyramid since slant height is not defined. To find the area, find the area of each face and the area of the base and add them.

Sauron [17]3 years ago

8 0

Total surface area of pyramid = area of base + area of 4 triangular faces

area of base = 6.4*6.4 = 40.96 cm²
area of one triangular face = 1/2 * 6.4 * 6.1 = 19.52 cm²

Surface area of pyramid = 40.96 + 4 * 19.52 = 119.04 cm²

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90 = p + x and

45 = q + x Subtracting the 2 equations:-

90 - 45 = p - q

Answer p - q = 45

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Veronika [31]

The expression of integral as a limit of Riemann sums of given integral $\int\limits^5_b {1} \, x/(2+x^{3}) dx$ is 4 $\lim_{n \to \infty}$ ∑ $n(n+4i)/2n^{3}+(n+4i)^{3}$ from i=1 to i=n.

Given an integral $\int\limits^5_b {1} \, x/(2+x^{3}) dx$ .

We are required to express the integral as a limit of Riemann sums.

An integral basically assigns numbers to functions in a way that describes displacement, area, volume, and other concepts that arise by combining infinite data.

A Riemann sum is basically a certain kind of approximation of an integral by a finite sum.

Using Riemann sums, we have :

$\int\limits^b_a {f(x)} \, dx$ = $\lim_{n \to \infty}$ ∑f(a+iΔx)Δx ,here Δx=(b-a)/n

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⇒Δx=(5-1)/n=4/n

f(a+iΔx)=f(1+4i/n)

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$\lim_{n \to \infty}$ ∑f(a+iΔx)Δx=

$\lim_{n \to \infty}$ ∑ $n^{2}(n+4i)/2n^{3}+(n+4i)^{3}4/n$

=4 $\lim_{n \to \infty}$ ∑ $n(n+4i)/2n^{3}+(n+4i)^{3}$

Hence the expression of integral as a limit of Riemann sums of given integral $\int\limits^5_b {1} \, x/(2+x^{3}) dx$ is 4 $\lim_{n \to \infty}$ ∑ $n(n+4i)/2n^{3}+(n+4i)^{3}$ from i=1 to i=n.

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