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1 year ago

80 years converted to sec

Mathematics

2 answers:

Dmitrij [34]1 year ago

6 0

Answer: 2522880000 seconds

Step-by-step explanation:

80(365) = 29200 days

29200(24) = 700800 hours

700800(60) = 42048000 minutes

42048000(60) = 2522880000 seconds

Rzqust [24]1 year ago

3 0

Answer:

2522880 000 is the answer

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AB = 5x -9; BC= -2x + 12

BaLLatris [955]

Answer:

X=-3

Step-by-step explanation:

5x - 9

-2x + 12

(+) (-)

7x = -21

X= -3

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2 years ago

Three tanks are capable of holding 361,841, and 901 of the greatest vessel winch can be used to fill each one of them on exact n

daser333 [38]

Answer:

Tank which is capable of holding 1 can fill each one of the tanks an exact number of time.

Step-by-step explanation:

Three tanks are capable of holding $361,841,901$

To find which tank can be used to fill each one of them an exact number of time, find $HCF(361,841,901)$

$361=19^2\\841=29^2\\901=17(53)$

Therefore,

$HCF(361,841,901)=1$

So, tank which is capable of holding 1 can fill each one of the tanks an exact number of time.

6 0

3 years ago

Will switching points when calculating distance affect the final answer? Explain.

scoray [572]

Answer:

I think it's B or C but I'm not sure cuz I'm struggling with this question also

3 0

2 years ago

Integrate e^x(sin(x) cos(x))

Karo-lina-s [1.5K]

$I=\int e^x(\sin(x)\cos(x))dx=\int e^x(\frac{1}{2}\sin(2x))dx=\frac{1}{2}\int e^x\sin(2x)dx$

$\text{If }u=\sin(2x)\to du=2\cos(2x)dx~\text{and}~dv=e^xdx\to v=e^x:\\\\
\text{Using }\int u\,dv=uv-\int v\,du:\\\\
I=\frac{1}{2}(e^x\sin(2x)-\int e^x(2\cos(2x))dx)\\\\
2I=e^x\sin(2x)-2\underbrace{\int e^x\cos(2x)dx}_{I_2}$

Looking for $I_2$ :

$\text{If}~u=\cos(2x)\to du=-2\sin(2x)dx~\text{and}~dv=e^xdx\to v=e^x:\\\\
I_2=e^x\cos(2x)-\int e^x(-2\sin(2x))dx\\\\ I_2=e^x\cos(2x)+2\int e^x(\sin(2x))dx\\\\ I_2=e^x\cos(2x)+2\int e^x(2\sin(x)\cos(x))dx\\\\ I_2=e^x\cos(2x)+4\int e^x(\sin(x)\cos(x))dx=e^x\cos(2x)+4I$

Replacing:

$2I=e^x\sin(2x)-2I_2\iff\\\\2I=e^x\sin(2x)-2(e^x\cos(2x)+4I)\iff\\\\
2I=e^x\sin(2x)-2e^x\cos(2x)-8I\iff\\\\
10I=e^x\sin(2x)-2e^x\cos(2x)\iff\\\\
I=\dfrac{e^x}{10}(\sin(2x)-2\cos(2x))\\\\
\boxed{\int e^x(\sin(x)\cos(x))dx=\dfrac{e^x}{10}(\sin(2x)-2\cos(2x))+C}$

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3 years ago

I need help with this geometry

Marysya12 [62]

2x - 3y = 9
- 3y = -2x + 9
y = (-2x + 9)/-3

slope = -2
Since the slope is negative the line passes through quadrants 2 and 4
Therefore the answer is b.

5 0

2 years ago