Well, you didn't say what language, so here's in Java:
public static void PrintShampooInstructions(int numCycles)
{
if(numCycles < 1)
System.out.println("Too few.");
else if (numCycles > 4)
System.out.println("Too many.");
else
{
for(int i = 1; i <= numCycles; i++)
{
System.out.println(i+": Lather and rinse.");
}
System.out.println("Done.");
}
}
And also in an image, in case you can't really see it
Answer would be D)potential
B
_______________________________________________________
Answer:
B
Explanation:
prefix 16 got 255.555.0.0 subnet mask & 65,536 total host. so in your case it ill take 172.16.0.0 - 172.16.255.255 / subnet and your scope ill take the 172.16.1.1 - 172.16.1.200 . for the next subnet is 172.17.0.0 - 172.17.255.255 and same thing as your scope you ill take 172.17.1.1 - 173.17.1.200 . keep learning bro :)
Answer:
a) D = 4.88 * 10^(-14) m^2 / s
b) <em>t </em>= 1.1 hr
Solution:
a) Magnesium in Aluminum diffusion:
D = Do * exp(-Qd / RT)
= (1.2 * 10^(-4) m^2 / s) * exp ( - 130,000 / 8.31 * 723.15)
= 4.88 * 10^(-14) m^2 / s
D = 4.88 * 10^(-14) m^2 / s
b) The composition remains same at say the distance Xo:
(Cx - Co) / (Cs - Co) = Constant
Xo^2 / D_{550} * <em>t </em>= Xo^2 / D_{450} * 15
D_{550} * <em>t </em>= D_{450} * 15
(1.2 * 10^(-4) m^2 / s) * exp ( - 130,000 / 8.31 * 723.15) * <em>t</em>
(4.88 * 10^(-14) m^2 / s) * 15
by, solving for <em>t </em>we get:
<em>t </em>= 1.1 hr
So, the time required is 1.1 hr.
