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____ [38]
3 years ago
12

The expression that is tested by a switch statement must have a(n) __________ value.

Computers and Technology
1 answer:
Hitman42 [59]3 years ago
6 0

The answer is relational.

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How many generations of computer languages have there been since the middle of the 20th century?
evablogger [386]
4 generations hahahaha
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3 years ago
Read 2 more answers
Write the following program in C++ to print:
Alenkinab [10]
1.
#include <iostream>#include <string>
using namespace std;
int main(){    string chars; // This is where we will put our @ signs and print them    for(int x=0;x < 5; x++){
        chars = chars + '@'; // This will concatenate an @ sign at the end of the variable        cout << chars << "\n";    }}

2.
#include <iostream>#include <string>
using namespace std;
int main(){    string name; // Our variable to store the name    cout << "What is your name? \n"; // Asks the user for their name    cin >> name;    cout << "\nWell, hello " << name << "!";}

3.
#include <iostream>#include <string>
using namespace std;
int main(){    int number; // Our variable    cout << "Enter a number\n"; // Asks for a number    cin >> number;    cout << "You entered " << number << "%!";}

4.
#include <iostream>#include <string>
using namespace std;
int main(){    int number; // Our variable    cout << "Enter a number\n";    cin >> number;
    int check = number % 2; // The modulo operator (the percent sign) gets the remainder of the quotient    if (check == 0) {        cout << number << " is even!"; // If the remainder is 0 then it prints out "x is even"    } else {        cout << number << " is odd!"; // If the remainder is not 0 then it prints out "x is odd"    }}

5.
#include <iostream>#include <string>
using namespace std;
int main(){    float r; // Our variable    cout << "Enter a radius\n";    cin >> r;    if (r < 0){        cout << "Lol. No."; // If the radius is less than zero print out that message    }    float circumference=2*3.14*r;    float area=r*r*3.14;    cout << "\n\n Circumference of circle: " << circumference;    cout << "\n Area of circle: " << area;}
4 0
3 years ago
You need a version of usb technology that will support older usb devices, of which you have many, as well as newer ones. what wo
tiny-mole [99]
The answer you're looking for might be "backwards-compatible".
7 0
3 years ago
Assume that to_the_power_of is a function that expects two integer parameters and returns the value of the first parameter raise
Bezzdna [24]

Answer:

The statement in python is as follows:

to_the_power_of(cube_side,3)

Explanation:

As stated as the requirement of the code segment, the statement takes as parameters a variable cube_side and a constant 3.

It then returns the volume of the cube; i.e. cube raise to power 3

<em></em>

<em>See full program below</em>

<em>def to_the_power_of(val,powe):</em>

<em>     result = val**powe</em>

<em>     print(result)</em>

<em>cube_side = float(input("Cube side: "))</em>

<em>to_the_power_of(cube_side,3)</em>

4 0
3 years ago
write a 2d array c program that can capture marks of 15 students and display the maximum mark, the sum and average​
bekas [8.4K]

Answer:

#include <stdio.h>  

int MaxMark(int* arr, int size) {

   int maxMark = 0;

   if (size > 0) {

       maxMark = arr[0];

   }

   for (int i = 0; i < size; i++) {

       if (arr[i] > maxMark) {

           maxMark = arr[i];

       }

   }

   return maxMark;

}

int SumMarks(int* arr, int size) {

   int sum = 0;

   for (int i = 0; i < size; i++) {

       sum += arr[i];

   }

   return sum;

}

float AvgMark(int* arr, int size) {

   int sum = SumMarks(arr, size);

   return (float)sum / size;

}

int main()

{

   int student0[] = { 7, 5, 6, 9 };

   int student1[] = { 3, 7, 7 };

   int student2[] = { 2, 8, 6, 1, 6 };

   int* marks[] = { student0, student1, student2 };

   int nrMarks[] = { 4, 3, 5 };

   int nrStudents = sizeof(marks) / sizeof(marks[0]);

   for (int student = 0; student < nrStudents; student++) {              

       printf("Student %d: max=%d, sum=%d, avg=%.1f\n",  

           student,

           MaxMark(marks[student], nrMarks[student]),

           SumMarks(marks[student], nrMarks[student]),

           AvgMark(marks[student], nrMarks[student]));

   }

   return 0;

}

Explanation:

Here is an example using a jagged array. Extend it to 15 students yourself. One weak spot is counting the number of marks, you have to keep it in sync with the array size. This is always a problem in C and would better be solved with a more dynamic data structure.

If you need the marks to be float, you can change the types.

3 0
3 years ago
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