You would use PEMDAS to solve this:
0.8 x 1.5 = 1.2
4 + 1.2 - 3
5.2 - 3
2.2 is your answer
(9,0) (0,9) choose any two points since it’s a straight line honey and the dk the difference between the two points
9-0
———. = 1
0-9
Consider that the slope-intercept form of the straight line with slope (m) and y-intercept (c) is given by,
![y=mx+c](https://tex.z-dn.net/?f=y%3Dmx%2Bc)
a.
Modify the given equation as,
![\begin{gathered} \frac{x}{3}+\frac{y}{2}=1 \\ \frac{y}{2}=-\frac{x}{3}+1 \\ y=-\frac{2}{3}x+2 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Cfrac%7Bx%7D%7B3%7D%2B%5Cfrac%7By%7D%7B2%7D%3D1%20%5C%5C%20%5Cfrac%7By%7D%7B2%7D%3D-%5Cfrac%7Bx%7D%7B3%7D%2B1%20%5C%5C%20y%3D-%5Cfrac%7B2%7D%7B3%7Dx%2B2%20%5Cend%7Bgathered%7D)
Thus, the equation in slope-intercept form can be written as,
![y=-\frac{2}{3}x+2](https://tex.z-dn.net/?f=y%3D-%5Cfrac%7B2%7D%7B3%7Dx%2B2)
b.
Modify the given equation as,
![\begin{gathered} 4x-3y+2=0 \\ 3y=4x+2 \\ y=\frac{4}{3}x+\frac{2}{3} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%204x-3y%2B2%3D0%20%5C%5C%203y%3D4x%2B2%20%5C%5C%20y%3D%5Cfrac%7B4%7D%7B3%7Dx%2B%5Cfrac%7B2%7D%7B3%7D%20%5Cend%7Bgathered%7D)
Thus, the equation in slope-intercept form can be written as,
![y=\frac{4}{3}x+\frac{2}{3}](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B4%7D%7B3%7Dx%2B%5Cfrac%7B2%7D%7B3%7D)
c.
Modify the given equation as,
![\begin{gathered} x-y=5(x-y) \\ x-y=5x-5y \\ 5y-y=5x-x \\ 4y=4x \\ y=x \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20x-y%3D5%28x-y%29%20%5C%5C%20x-y%3D5x-5y%20%5C%5C%205y-y%3D5x-x%20%5C%5C%204y%3D4x%20%5C%5C%20y%3Dx%20%5Cend%7Bgathered%7D)
Thus, the equation in slope-intercept form can be written as,
Answer:
10,5
Step-by-step explanation:
Answer:
j = $15
t = $5
Step-by-step explanation:
This question can be solved using simultaneous equation
let the price of t-shirt be represented with t
let the price of jeans be represented with j
From the question, these two equations can be derived
2j + 6t = 60 eqn 1
4j + 3t = 75 eqn 2
multiply eqn 1 by 2
4j + 12t = 120 eqn 3
Subtract eqn 2 from 3
9t = 45
divide both sides by 5
t = 5
Substitute for t in eqn 1
2j + 6(5) = 60
2j = 30
j = 15