<span>Line ET is tangent to circle A at T
</span>
∴ ET ⊥ TN
∴ ∠ ETN = 90
<span>the measure of Arc TG = 70
</span>
∠ TNG = half <span>the measure of Arc TG = 0.5 *70 = 35
</span>
<span>Δ ETN ⇒ The sum of all angles = 180
</span>
<span>∴∠ GET = ∠ NET = 180 - (90 + 35 ) = 55
</span>
∴ The correct answer is option <span>A. 55°</span>
AZ^2= 2^2 + 2^2 = 8
AP^2 = ZP^2 = 5^2 + 7^2 = 74
P^2of APZ = /8 + 74*2 =156
P= 12.489
Answer:
The cost per print expressed as a slope is 7.125
Step-by-step explanation:
To calculate the cost per print, let’s envision that we have a graphical representation of cost of posters against the number of posters
We have the cost on the y-axis and the number of posters on the x axis
With the information given in the question, we shall be having two data points
Point 1 = (32,126)
point 2 = (48,240)
Now to find the slope of the line which is cost per print, we make use of both points in the slope equation.
Mathematically, slope m will be
m = y2-y1/x2-x1
Thus, we have;
m = (240-126)/(48-32)
m = 114/16
m = 7.125
The cost per print expressed as a slope is 7.125
The answer to this question is 1,193,400,00 ml of gasoline. We can reach this conflusion through the following equation:
3.9
x 10^3 10 x 10 x 103.9 x 1,0003,900 ml per second. Then, to work out
how many ml are burned in a minute, multiply 3,900 by 60. Therefore, we
can establish that ne commercial airplane burns around 234,000 ml of
gasoline per minute. Next, consider the equation 5.1 x 10^35.1 x 10 x 10
x 105.1 x 1,0005,100. From this, we can work out that 5,100 airplanes
burn 1,193,400,000 ml of gasoline in one minute.
V=127.16pi m^3
The formula for the Volume of a Cylinder is V=(pi)r^2h
First we have to fill in the variables with the information we have. The radius is 3.4m. The height is 11m. We want to leave the answer in terms of pi, so we won't multiply by pi at all. Let's plug it in.
V=(pi)3.4^2•11
To square a number we multiply it by itself, so 3.4 • 3.4 equals 11.56.
V=(pi)11.56•11
Next, we multiply the radius squared, which we already found by the height of the cylinder which is 11. 11.56 times 11 equals 127.16.
V=127.16pi
We found the final answer and don't use pi since we want it in terms of pi. Since a Cylinder is a 3-D figure, that means the units of measurement is cubed.
The answer is A) 127.16pi m^3
