Is there any graphs ? can you mark me as brainlist :)?
To solve this, you have to know that the first derivative of a function is its slope. When an interval is increasing, it has a positive slope. Thus, we are trying to solve for when the first derivative of a function is positive/negative.
f(x)=2x^3+6x^2-18x+2
f'(x)=6x^2+12x-18
f'(x)=6(x^2+2x-3)
f'(x)=6(x+3)(x-1)
So the zeroes of f'(x) are at x=1, x=-3
Because there is no multiplicity, when the function passes a zero, he y value is changing signs.
Since f'(0)=-18, intervals -3<x<1 is decreasing(because -3<0<1)
Thus, every other portion of the graph is increasing.
Therefore, you get:
Increasing: (negative infinite, -3), (1, infinite)
Decreasing:(-3,1)
Answer:
Multiplication equation 6 t = 54 6t = 54 6t=54 Multiply each side by five.
Answer:
x + 10
Step-by-step explanation:
X is used to represent a variable or any number. This letter can be changed if you'd like
South west
Shifting 4 units left (decreasing in x-axis by 4 units)
Shifting 5 units down (decreasing in y-axis by 5 units)
Apply to every vertices coordinates(x - 4, y - 5)
New coordinates
A(-2, -1)
B(-1, -4)
C(1,0)
