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aleksley [76]
3 years ago
15

1. Jack says "six less than a number is tour" is written as 6-n = 4. Jane says he is incorrect and

Mathematics
1 answer:
seropon [69]3 years ago
4 0

Answer:

well it really depends on how and what number you put for the n like I put 10 and so the way jane said it should be doesnt work because 10-6 just doesnt make sense and you could do it a different way but if you had do 10-6 it wouldve been in the negatives and it wouldnt have been 4 so in this case we have more choices so I would say jack is right because it is more reasonable to do 6-n=4 and instead of the n we put a 10

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Answer:

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Step-by-step explanation:

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Which set of numbers represents a Pythagorean triple
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Answer:

27,36,45

Step-by-step explanation:

Pythagorean theorem

a^{2} +b^{2} =c^{2}

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In Area A, the insurance coverage rate for a wood frame house is 0.46%. In Area B, the insurance coverage rate for a wood frame
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5 0
3 years ago
Solve the equation.<br> 4s=2/5<br><br> s=<br> (Type a whole number, fraction, or mixed number.)
BabaBlast [244]

Answer:

s = 1/10

Step-by-step explanation:

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*In ∆ABC, on the extension of the side BC , draw a line segment CD ≅ CA . Draw the segment AD . The line segment CE is the angle
Leya [2.2K]

CE ⊥ CF because m∠ECA + m∠FCA = 90°

Step-by-step explanation:

In ∆ABC

  • On the extension of the side BC , draw a line segment CD ≅ CA
  • Draw the segment AD
  • The line segment CE is the angle bisector of ∠ACB
  • The line segment CF is the median towards AD in ∆ ACD

We want to prove that CF ⊥ CE

Look to the attached figure

In Δ ABC

∵ CE is the bisector of angle ACB

∴ ∠ACE ≅ ∠BCE

In Δ ACD

∵ CA = CD

∴ Δ ACD is an isosceles triangle

∵ AD is the median towards AD

- In any isosceles triangle the median from a vertex to its opposite

  side bisects this vertex

∴ AD bisects ∠ACD

∴ ∠ACF ≅ ∠DCF

∵ BCD is a straight segment

∵ CE , CA , CF are drawn from point C

∴ m∠BCE + m∠ACE + m∠ACF + m∠DCF = 180°

∵ m∠ACE ≅ m∠BCE

∵ m∠ACF ≅ m∠DCF

- Replace m∠BCE by m∠ACE and m∠DCF by m∠ACF

∴ m∠ACE + m∠ACE + m∠ACF + m∠ACF = 180°

∴ 2 m∠ACE + 2 m∠ACF = 180°

- Divide all terms by 2

∴ m∠ACE + m∠ACF = 90°

∴ EC ⊥ CF

CE ⊥ CF because m∠ECA + m∠FCA = 90°

Learn more:

You can learn more about perpendicular lines in brainly.com/question/11223427

#LearnwithBrainly

7 0
3 years ago
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