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3 years ago

7

Nancy buys 15 m of ribbon. Her sister buys 6 m less ribbon but pays twice as much per metre. Together they pay R66. What is the

price per metre of each type of ribbon?

1 answer:

Katarina [22]3 years ago

4 0

Answer: 44/9 ----> 22/9

I hope this helps you

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Given tanx=8/15 when pi < x < 3pi/2, find tan x/2.

S_A_V [24]

Answer:

$tan(x/2)=-4$

Step-by-step explanation:

we know that

The angle x belong to the III quadrant -----> given problem

step 1

Find the angle x

$x=arctan(8/15)=28.07\°$

Remember that the angle x belong to the III Quadrant

so

$x=28.07\°+180\°=208.07\°$

step 2

Find angle x/2

$x/2=208.07\°/2=104.035\°$

step 3

Find tan(x/2)

$tan(104.035\°)=-4$

8 0

3 years ago

Use the unit circle to evaluate these expressions:

sergeinik [125]

Answer:

a) We can remove the complete rotations around the unitary circle like this, because we know that one complete revolution is equivalent to $2\pi$ :

$17 \pi/4 - 2\pi = \frac{9\pi}{4} -2\pi = \pi/4$

For this case we know that $sin (\pi/4) = \frac{\sqrt{2}}{2}$

So then $sin(\frac{17 \pi}{4}) = \frac{\sqrt{2}}{2}$

b) We can remove the complete rotations around the unitary circle like this, because we know that one complete revolution is equivalent to $2\pi$ :

$19 \pi/6 - 2\pi = \frac{7\pi}{6}$

For this case we know that $cos (\pi/6) = \frac{\sqrt{3}}{2}$

And we know that $\frac{7\pi}{6}$ is on the III quadrant since is equivalent to 210 degrees. And on the III quadrant the cosine is negative. So then $cos(\frac{19 \pi}{6}) = -\frac{\sqrt{3}}{2}$

c) For this case that any factor of $\pi$ the sin function is equal to 0.

So from definition of tan we have this:

$tan (450\pi) = \frac{sin(450 \pi)}{cos(450 \pi)}= \frac{0}{cos(450\pi)}= 0$

Step-by-step explanation:

a. sin (17pi / 4 )

We can remove the complete rotations around the unitary circle like this, because we know that one complete revolution is equivalent to $2\pi$ :

$17 \pi/4 - 2\pi = \frac{9\pi}{4} -2\pi = \pi/4$

For this case we know that $sin (\pi/4) = \frac{\sqrt{2}}{2}$

So then $sin(\frac{17 \pi}{4}) = \frac{\sqrt{2}}{2}$

b. cos (19pi / 6 )

We can remove the complete rotations around the unitary circle like this, because we know that one complete revolution is equivalent to $2\pi$ :

$19 \pi/6 - 2\pi = \frac{7\pi}{6}$

For this case we know that $cos (\pi/6) = \frac{\sqrt{3}}{2}$

And we know that $\frac{7\pi}{6}$ is on the III quadrant since is equivalent to 210 degrees. And on the III quadrant the cosine is negative. So then $cos(\frac{19 \pi}{6}) = -\frac{\sqrt{3}}{2}$

c. tan(450pi)

For this case that any factor of $\pi$ the sin function is equal to 0.

So from definition of tan we have this:

$tan (450\pi) = \frac{sin(450 \pi)}{cos(450 \pi)}= \frac{0}{cos(450\pi)}= 0$

4 0

3 years ago

If bowling costs $15 and shoe rentals 4$ and o spent 35$ how many games did I play

Rudiy27

Well if we add 15 + 15 + 4, we get 34, which, when we include tax, is about $35. So you played 2 games. Hope that helps!

8 0

4 years ago

Read 2 more answers

8. Madison uses 54 beads to make one necklace. If Madison has 2,185 beads, how many necklaces can she make and how many beads wo

hram777 [196]

Answer:

B) 40 necklaces with 25 left over

Step-by-step explanation:

7 0

3 years ago

This is based off my previous question asked. please help!

Nana76 [90]

Answer:

30

Step-by-step explanation:

just trust me A+ here you come

6 0

3 years ago

Read 2 more answers