Answer:
The exact value of tan(M) is 5/12 ⇒ answer (C)
Step-by-step explanation:
* Lets revise the trigonometry functions
- In ΔABC
# m∠B = 90°
# Length of AB = a , length of BC = b and length of AC = c
# The trigonometry functions of angle C are
- sin(C) = a/c ⇒ opposite side to ∠C ÷ the hypotenuse
- cos(C) = b/c ⇒ adjacent side to ∠C ÷ the hypotenuse
- tan(c) = a/b ⇒ opposite side to ∠C ÷ adjacent side to ∠C
* Now lets solve the problem
- In ΔONM
∵ m∠N = 90°
∵ MN = 12
∵ ON = 5
∵ tan(M) = ON/NM ⇒ opposite side of ∠(M) ÷ adjacent side of ∠(M)
∴ tan(M) = 5/12
* The exact value of tan(M) is 5/12
Answer:
22.29% probability that both of them scored above a 1520
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

The first step to solve the question is find the probability that a student has of scoring above 1520, which is 1 subtracted by the pvalue of Z when X = 1520.
So



has a pvalue of 0.5279
1 - 0.5279 = 0.4721
Each students has a 0.4721 probability of scoring above 1520.
What is the probability that both of them scored above a 1520?
Each students has a 0.4721 probability of scoring above 1520. So

22.29% probability that both of them scored above a 1520
Answer:
The answer is 17
A function is a relation in which each possible input value leads to exactly one output value. For example, we say “the output is a function of the input.”
Step-by-step explanation:
f(-7)=3-2x
3-2(-7)
3 - -14= 17