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3 years ago

What is 763 divided by8

Mathematics

1 answer:

Murrr4er [49]3 years ago

7 0

Answer: 763 divided by 8 equals 95.375 .

Step-by-step explanation: Just put it on a piece of paper and divide.

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Answer this correctly for the brainliest answer

Lilit [14]

Answer:

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Step-by-step explanation:

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2 years ago

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Help meeeee!!!!!! Please

Over [174]

Answer:

-1/11

Step-by-step explanation:

if this is one of the answer choices.

6 0

3 years ago

a deli sells a sandwich spread for 6.40 per pound. how much do you have to pay for 24 ounces of the spread

rjkz [21]

In the given question the most important part is convert ounce to pound and then the problem becomes easy. We already know
1 ounce = 0.0625 pounds
Then
24 ounce = 0.0625 * 24 pounds
= 1.5 pounds
Now let us focus on the problem in hand and the information's that are already given in the question.
The cost per pound of the sandwich sold by Deli = 6.40
Then
The cost of 1.5 pound of sandwich sold by Deli = 6.40 * 1.5
= 9.60
So the cost of 24 ounces of spread is 9.60.

3 0

2 years ago

Read 2 more answers

The probability that a certain hockey team will win any given game is 0.3723 based on their 13 year win history of 385 wins out

Whitepunk [10]

Answer:

0.1505 = 15.05% probability that the hockey team wins 6 games in November

Step-by-step explanation:

For each game, there are only two possible outcomes. Either the team wins, or it does not. The probability of winning a game is independent of winning other games. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The probability that a certain hockey team will win any given game is 0.3723

So $p = 0.3723$

12 games in November

So $n = 12$

What is the probability that the hockey team wins 6 games in November?

This is $P(X = 6)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 6) = C_{12,6}.(0.3723)^{6}.(1-0.3723)^{6} = 0.1505$

0.1505 = 15.05% probability that the hockey team wins 6 games in November

4 0

2 years ago

Show all work please!!!!!!

sergij07 [2.7K]

The midpoint formula is:
(point1 + point2)/2

1) (-2 + 12)/2 = 5

2) (-1 +5)/2 = 2
    (0+2)/2 = 1
     (2,1)

3) Sqrt of (x2-x1)^2 + (y2 - y1)^2
     sqrt of (7 -1)^2 + (-7 - 1)^2
     sqrt of (6)^2 + (-8)^2
     sqrt of 36 + 64
     sqrt of 100
     10

Hope this helps!

7 0

3 years ago