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sashaice [31]
2 years ago
13

Simplify the expression.

Mathematics
1 answer:
denis23 [38]2 years ago
8 0

Answer:

option d

Step-by-step explanation:

\sf \boxed{a^m*a^n = a^{m+n}\\\\}

\sf \left(\frac{m^{-1}m^{5}}{m^{-2}} \right)^{-3} =\left(\dfrac{m^{-1+5}}{m^{-2}}\right)^{-3}

                 \sf = \left(\dfrac{m^4}{m^{-2}}\right)^{-3}\\\\

\boxed{\dfrac{a^{m}}{a^{n}}=a^{m+n}}

                    \sf = \left(m^{4-[-2]}\right)^{-3}\\\\      =\left(m^{4+2}\right)^{-3}\\\\       = \left(m^6\right)^{-3}\\\\

\boxed{(a^{m})^n=a^{m*n}}

                    \sf= m^{6*(-3)}\\\\    = m^{-18}

\boxed{a^{-m}=\dfrac{1}{a^m}}

                    \sf=\dfrac{1}{m^{18}}

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Previous concepts  

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".  

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X \sim Binom(n=15, p=0.90)  

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P(X)=(nCx)(p)^x (1-p)^{n-x}  

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P(X \geq 13) = P(X=13) +P(X=14) +P(X=15)

P(X=13)=(15C13)(0.9)^{13} (1-0.9)^{15-13}=0.267  

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Part b

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Since our calculated probability is too higher compared to 0.05 we can conclude this:

D. No​, because the probability of this occurring is not small.

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