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3 years ago

What is the ratio of x to y? 3x = 8y

Mathematics

1 answer:

skelet666 [1.2K]3 years ago

4 0

The answer is 8/3

3x= 8y

x 8
-- = ---
y 3

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An acre measures 4840 square yards. In a city, a lot on which a single-

belka [17]

The lot is 9.2% of the an acre.

Given:

Area of an acre = 4840 sq. yards

Area of lot = 40 by 100 ft = $40 ]\times 100 = 4,000 $ ft^{2}$

Convert the area of the lot to feet ( $9 ft^{2} = yd^{2}$ ):

Therefore:

Area of lot = $\frac{4,000}{9} = 444.4 $ yd^{2}$

Percentage occupied by the lot = area of lot / area of acre x 100

$= \frac{444.4}{4840} \times 100\\\= 9.2$

The lot therefore is 9.2% of the an acre.

Learn more here:

brainly.com/question/20730855

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2 years ago

What is the equation of the line that passes through the point (4,-2)(4,−2) and has a slope of -2−2?

Sonbull [250]

i believe the answer is y = -2x + 6

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2 years ago

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The radioactive isotope radium has a half-life of 1,600 years. The mass of a 100-gram sample of radium will be______ grams after

Olenka [21]

To solve this we are going to use the half life equation $N(t)=N_{0} e^{( \frac{-0.693t}{t _{1/2} }) }$
Where:
$N_{0}$ is the initial sample
$t$ is the time in years
$t_{1/2}$ is the half life of the substance
$N(t)$ is the remainder quantity after $t$ years

From the problem we know that:
$N_{0} =100$
$t=200$
$t_{1/2} =1600$

Lets replace those values in our equation to find $N(t)$ :
$N(200) =100e^{( \frac{(-0.693)(200)}{1600}) }$
$N(200)=100e^{( \frac{-138.6}{1600} )}$
$N(200)=100e^{-0.086625}$
$N(200)=91.7$

We can conclude that after 1600 years of radioactive decay, the mass of the 100-gram sample will be 91.7 grams.

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3 years ago

Write the equation of the vertical line that passes through ordered pair 2.

damaskus [11]

Answer:

this is a table

y= (a times when y is negative)

X=(X is possitive)