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3 years ago

Two different isosceles triangle with perimeter for 4a+b

1 answer:

6 0

Side 1 + Side 2 + Side 3 = Perimeter

First isosceles triangle: 2a + 2a + b = 4a + b

Second isosceles triangle: b/2 + b/2 + 4a = 4a + b

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Find the distance between the two points in simplest radical form.

emmainna [20.7K]

The distance between the two points is $2\sqrt{5}$

Explanation:

Given that the two points are $(-8,-2)$ and $(-6,2)$

We need to determine the distance between the two points in simplest radical form.

The distance between the two points can be determined using the distance formula,

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Let us substitute the coordinates $(-8,-2)$ and $(-6,2)$ in the above formula, we get,

$d=\sqrt{(-6+8)^2+(2+2)^2}$

Simplifying the terms, we get,

$d=\sqrt{(2)^2+(4)^2}$

Squaring the terms, we get,

$d=\sqrt{4+16}$

Adding, we get,

$d=\sqrt{20}$

Simplifying, we have,

$d=2\sqrt{5}$

Thus, the distance between the two points in simplest radical form is $2\sqrt{5}$

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4 years ago

Alinewithaslopeof7passesthroughthepoint

Dahasolnce [82]

Y=7x+3 because slope intercept form is y=mx+b where x is the slope and b is the y intercept so when you plug in the slope of 7 and the y intercept of 3 you get the equation y=7x+3.

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4 years ago

Find the average of e^-x over [0,3]

yaroslaw [1]

The average value of a continuous function f(x) over an interval [a, b] is given by the integral,

$\displaystyle \frac1{b-a}\int_a^b f(x)\,\mathrm dx$

Compute the integral for f(x) = e ⁻ˣ over [0, 3] :

$\displaystyle \frac1{3-0}\int_0^3e^{-x}\,\mathrm dx=\frac13(-e^{-x})\bigg|_0^3=\frac13(-e^{-3}-(-e^{-0})) = \frac13 \left(1-\frac1{e^3}\right) = \boxed{\frac{e^3-1}{3e^3}}$

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3 years ago

Need help with a math question

makkiz [27]

Answer:

b = 17

Step-by-step explanation:

The angle bisector of the apex angle of an isosceles triangle is also a median and altitude. PS=RS=17

b = 17

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3 years ago

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Answer:

Step-by-step explanation:

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