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damaskus [11]
2 years ago
8

A superhero has been called to rescue the planet from destruction. He leaves from a point on the equator and flies along the equ

ator at 60,000 m/min. At the same time his partner flies from thee same location in the opposite direction at 4415 km/h. Please explain why
Mathematics
1 answer:
Alchen [17]2 years ago
6 0

The superhero moves at 3600 km/h and his partner at 4415 km/h. The earth is round, so both him and his partner can get to the same location even travelling at opposite directions.

<h3>What is speed?</h3>

Speed is the ratio of distance travelled to the total time taken, it is given by:

Speed = distance / time

The superhero flies at 60000 m/min = (60000m * 1 km per 1000 m) / (1 min * 1 hr per 60 min) = 3600 km/h

The earth is round, so both him and his partner can get to the same location even travelling at opposite directions.

Find out more on speed at: brainly.com/question/4931057

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Answer:

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Step-by-step explanation:

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3 years ago
The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e
Korolek [52]

Answer:

A sample of 499 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is given by:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

In this question, we have that:

\pi = 0.21

90% confidence level

So \alpha = 0.1, z is the value of Z that has a pvalue of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

How large a sample would be required in order to estimate the fraction of tenth graders reading at or below the eighth grade level at the 90% confidence level with an error of at most 0.03

We need a sample of n, which is found when M = 0.03. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.645\sqrt{\frac{0.21*0.79}{n}}

0.03\sqrt{n} = 1.645\sqrt{0.21*0.79}

\sqrt{n} = \frac{1.645\sqrt{0.21*0.79}}{0.03}

(\sqrt{n})^2 = (\frac{1.645\sqrt{0.21*0.79}}{0.03})^2

n = 498.81

Rounding up

A sample of 499 is needed.

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3 years ago
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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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