3 years ago

How would you solve -7x-4y=16

1 answer:

8 0

So one easy way is to make the equation equal to only one place holder so
-7x-4y=16
add 7x to both sdies
-4y=16+7x
multiply both sides by -1
4y=-16-7x
divide both sides by 4
y=-4-7/4x
subsitute values for x and get values for y
exg
if x=0 then y=-4
if x=1 then y=-5 3/7
etc

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Anyone knows how to do 4a)

Olin [163]

Sure. Brainly just made me an Ace.

Let's plug in 1/x as the independent and xy as the dependent in point slope form:

$xy = m (\frac 1 x) + b = \frac m x + b$

We have two points (1/x,xy)=(-4,-2) and (1/x,xy)=(3,5)

That's a slope

$m = \dfrac{5- -2}{3 - -4} = 1$

So a y intercept

5 = 3 + b

b = 2

$xy = \dfrac 1 x + 2 = \dfrac{2x + 1}{x}$

That's easy to solve for y:

$y =\dfrac{2x+1}{x^2}$

When x=1 that's

$y = \dfrac{2+1}{1} = 3$

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3 years ago

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Korolek [52]

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2 years ago

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Andru [333]

Quadrant 4
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