It is given thatΔ QRS ≅Δ TUV
Out of all the given options
(C) QS= TV [C P C T}
(D) QR =TU
(E) S = V
(F) R= U
C, D,E, F are correct options.
Because when two triangles are congruent their corresponding parts are equal.
CPCT means corresponding parts of congruent triangles.
All these options are congruent by CPCT.
Side QR is congruent to TU.
Side Q S is congruent to TV.
Angle S is Congruent to Angle V.
Angle R is congruent to Angle U.
The meaning of congruency of shapes is that the two or many more shapes are identical.
Answer:
482 km
63.94 degrees
Step-by-step explanation:
to solve this question we will use the cosine rule. For starters, draw your diagram. From point A, up north is 500km and 060 from there, another 300. If you join the point from the road junction back to the starting point, yoou have a triangle.
Cosine rule states that
C = 
where both A and B are the given distances, 500 and 300 respectively, C is the 3rd distance we're looking for and c is the given angle, 060
solving now, we have
C = 
C = ![\sqrt{250000 + 90000 - [215000 cos(60) }]](https://tex.z-dn.net/?f=%5Csqrt%7B250000%20%2B%2090000%20-%20%5B215000%20%20%20cos%2860%29%20%20%7D%5D)
C = ![\sqrt{340000 - [215000 * 0.5 }]](https://tex.z-dn.net/?f=%5Csqrt%7B340000%20-%20%5B215000%20%2A%200.5%20%20%7D%5D)
C = ![\sqrt{340000 - [107500 }]](https://tex.z-dn.net/?f=%5Csqrt%7B340000%20-%20%5B107500%20%20%7D%5D)
C =
C = 482 km
The bearing can be gotten by using the Sine Rule.
= 
sina/500 = sin60/482
482 sina = 500 sin60
sina = 
sina = 0.8983
a = sin^-1(0.8983)
a = 63.94 degrees
Answer:
C, D
Step-by-step explanation:
I assume your problem statement actually says
x - 54 > -76
x > -22
then the answers
C, D
are part of the solution set.
the others are not.
Answer:
21
Step-by-step explanation:
yeah 2+2 is 21 thanks for the very nonexistent question