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k0ka [10]
3 years ago
6

Consider a fair coin which when tossed results in either heads (H) or tails (T). If the coin is tossed TWO times 1. List all pos

sible outcomes. (Order matters here. So, HT and TH are not the same outcome.) 2. Write the sample space. 3. List ALL possible events and compute the probability of each event, assuming that the probability of each possible outcome from part (a) is equal. (Keep in mind that there should be many more events than outcomes and not all events will have the same probability.)
Mathematics
1 answer:
Volgvan3 years ago
4 0

Answer:

Sample space = {(T,T), (T,H), (HT), (HH)}

Step-by-step explanation:

We are given a fair coin which when tossed one times either gives heads(H) or tails(T).

Now, the same coin is tossed two times.

1) All the possible outcomes

Tails followed by tails

Rails followed by heads

Heads followed by a tail

Heads followed by heads

2) Sample space

{(T,T), (T,H), (HT), (HH)}

3) Formula:

Probability = \displaystyle\frac{\text{Favourable outcome}}{\text{Total number of outcome}}

Using the above formula, we can compute the following probabilities.

Probability((T,T)) =\frac{1}{4}

Probability((T,H)) =\frac{1}{4}

Probability((H,T)) =\frac{1}{4}

Probability((H, H)) =\frac{1}{4}

Probability(Atleast one tails) = \frac{3}{4}

Probability(Atleast one heads) = \frac{3}{4}

Probability(Exactly one tails) = \frac{2}{4}

Probability(Exactly one heads) = \frac{2}{4}

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()) A rectangular piece of paper has a perimeter of 22 inches and an area of 28 square
Natasha2012 [34]

Given:

Perimeter of a rectangular paper = 22 inches.

Area of the rectangular paper = 28 square inches.

To find:

The dimensions of the rectangular paper.

Solution:

Let l be the length and w be the width of the rectangular paper.

Perimeter of a rectangle is:

P=2(l+w)

Perimeter of a rectangular paper is 22 inches.

2(l+w)=22

l+w=\dfrac{22}{2}

l=11-w                      ...(i)

Area of a rectangle is:

A=lw

Area of the rectangular paper is 28 square inches.

28=lw

Using (i), we get

28=(11-w)w

28=11w-w^2

w^2-11w+28=0

Splitting the middle term, we get

w^2-7w-4w+28=0

w(w-7)-4(w-7)=0

(w-7)(w-4)=0

Using zero product property, we get

(w-7)=0\text{ and }(w-4)=0

w=7\text{ and }w=4

If w=7, then by using (i)

l=11-7

l=4

If w=4, then by using (i)

l=11-4

l=7

Therefore, the dimensions of the paper are either 7\times 4 or 4\times 7.

5 0
3 years ago
HELP PLEASE ILL GIVE THE BRANLIEST THING IF U DO, PLEASEE
bezimeni [28]

Answer:

The y-intercept is 5, and the slope is -3/2, y=5

Step-by-step explanation:

8 0
2 years ago
Multiple-choice questions each have four possible answers left parenthesis a , b , c , d right (a, b, c, d)​, one of which is co
arlik [135]
A) Since there are four multiple choice questions Which has one correct answer. The probability of choosing a correct answer is

P(C) = \frac{1}{4}

The probability of choosing wrong answer is

P(W) = \frac{3}{4}

Using the multiplication rule
P(WWC) = P(W) \times P(W) \times P(C) \\ \\ P(WWC) = \frac{3}{4} \times \frac{3}{4} \times \frac{1}{4} \\ \\ P(WWC) = \frac{9}{64}

b) If you guess answers to three of the questions, then the possibilities of getting one correct answer are:

Either the first two are wrong and the third one is correct. This will give the arrangement;

WWC

Or the first is wrong the second one is correct and the last one is wrong. This will give the arrangement,

WCW

Or the first one is correct and the last two are wrong. This will give the arrangement,

CWW
.

P(WWC) = P(W) \times P(W) \times P(C) \\ \\ P(WWC) = \frac{3}{4} \times \frac{3}{4} \times \frac{1}{4} \\ \\ P(WWC) = \frac{9}{64}

P(WCW ) = P(W) \times P( C ) \times P(W) \\ \\ P(WCW) = \frac{3}{4} \times \frac{1}{4} \times \frac{3}{4} \\ \\ P(WCW) = \frac{9}{64}

P(CWW ) = P(W) \times P( C ) \times P(W) \\ \\ P(CWW) = \frac{1}{4} \times \frac{3}{4} \times \frac{3}{4} \\ \\ P(CWW) = \frac{9}{64}

c) The probability of getting one correct answer is either the first one is correct or second is correct or third is correct.

P(One \: Correct)= P(CWW) \: or P(WCW) \: or \: P(WWC) \\ \\ P(One \: Correct)= P(CWW) \: + P(WCW) \: + \: P(WWC) \\ \\ P(One \: Correct)= \frac{9}{64} + \frac{9}{64} + \frac{9}{64}  \\ \\ P(One \: Correct) = \frac{27}{64}
7 0
4 years ago
Read 2 more answers
Determine the interval(s)on which the function is strictly increasing.
Angelina_Jolie [31]
Check the picture below.

4 0
4 years ago
Find the lengths of the sides of the triangle PQR. P(2, −3, −4), Q(8, 0, 2), R(11, −6, −4) |PQ| = Incorrect: Your answer is inco
Aloiza [94]

Answer:

the length PQ is 9 units,the length QR is 9 units,the length PR is 9.48 units,the triangle is not a right triangle,this is a isosceles triangle

Step-by-step explanation:

Hello, I think I can help you with this

If  you know two points, the distance between then its given by:

P1(x_{1},y_{1},z_{1} ) \\P2(x_{2},y_{2},z_{2})\\\\d=\sqrt{(x_{2}-x_{1} )^{2} +(y_{2}-y_{1}  )^{2}+(z_{2}-z_{1} )^{2} }

Step 1

use the formula to find the length PQ

Let

P1=P=P(2, −3, −4)

P2=Q=Q(8, 0, 2)

d=\sqrt{(8-2)^{2} +(0-(-3))^{2}+(2-(-4))^{2}} \\ d=\sqrt{(6)^{2} +(3)^{2}+(6 )^{2}}} \\d=\sqrt{36+9+36}\\d=\sqrt{81} \\d=9\\

the length PQ is 9 units

Step 2

use the formula to find the length QR

Let

P1=Q=Q(8, 0, 2)

P2=R= R(11, −6, −4)

d=\sqrt{(11-8)^{2} +(6-0))^{2}+(-4-2 )^{2}}  \\\\\\d=\sqrt{(3)^{2} +(6)^{2}+(-6 )^{2}}} \\d=\sqrt{9+36+36}\\d=\sqrt{81} \\d=9\\

the length QR is 9 units

Step 3

use the formula to find the length PR

Let

P1=P(2, −3, −4)

P2=R= R(11, −6, −4)

d=\sqrt{(11-2)^{2} +(-6-(-3)))^{2}+(-4-4 )^{2}}  \\\\\\d=\sqrt{(9)^{2} +(-6+3)^{2}+(-4-(-4) )^{2}}} \\d=\sqrt{81+9+0}\\d=\sqrt{90} \\d=9.48\\

the length PR is 9.48 units

Step 4

is it a right triangle?

you can check this by using:

side^{2} +side^{2}=hypotenuse ^{2}

Let

side 1=side 2= 9

hypotenuse = 9.48

Put the values into the equation

9^{2} +9^{2} =9.48^{2}\\ 81+81=90\\162=90,false

Hence, the triangle is not a right triangle

Step 5

is it an isosceles triangle?

In geometry, an isosceles triangle is a type of triangle that has two sides of equal length.

Now side PQ=QR, so this is a isosceles triangle

Have a great day

3 0
3 years ago
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