I think x would equal 7 because when y=75 and x=25, x is one third of y so one third of 21 is 7
Answer:Well, I don't know what you got so I can't tell you if it is right.
If it works in both equations, it depends of whether your equations are set up correctly.
Here is how I would do this problem.
Let x = no. of hot dogs,y = number of sodas.
First equation is just about the number of things.
x + y = 15
Second equation is about the cost of things.
1.5 x + .75 y = 18
solve x+y = 15 for y y = 15-x substitute into second equation
1.5x + .75(15 - x) = 18
You should get the correct answer for number of hot dogs if you solve this correctly. Put your answer in the x + y =15 equation to get y. Then put both x and y into the cost equation and check your answer.
Hope this helps.
Step-by-step explanation:
Answer:
x<6/5, x>14/5
Step-by-step explanation:
Steps
$5\left|x-2\right|+4>8$
$\mathrm{Subtract\:}4\mathrm{\:from\:both\:sides}$
$5\left|x-2\right|+4-4>8-4$
$\mathrm{Simplify}$
$5\left|x-2\right|>4$
$\mathrm{Divide\:both\:sides\:by\:}5$
$\frac{5\left|x-2\right|}{5}>\frac{4}{5}$
$\mathrm{Simplify}$
$\left|x-2\right|>\frac{4}{5}$
$\mathrm{Apply\:absolute\:rule}:\quad\mathrm{If}\:|u|\:>\:a,\:a>0\:\mathrm{then}\:u\:<\:-a\:\quad\mathrm{or}\quad\:u\:>\:a$
$x-2<-\frac{4}{5}\quad\mathrm{or}\quad\:x-2>\frac{4}{5}$
Show Steps
$x-2<-\frac{4}{5}\quad:\quad x<\frac{6}{5}$
Show Steps
$x-2>\frac{4}{5}\quad:\quad x>\frac{14}{5}$
$\mathrm{Combine\:the\:intervals}$
$x<\frac{6}{5}\quad\mathrm{or}\quad\:x>\frac{14}{5}$
Let the leading term of the polynomial, f(x), be axⁿ.
Examine the possibilities.
n a x -> - ∞ x -> +∞
------- ---- ----------- ------------
even a>0 f -> +∞ f -> +∞ Not true
even a<0 f-> - ∞ f-> -∞ True
odd a>0 f-> -∞ f-> +∞ Not true
odd a<0 f-> +∞ f-> -∞ Not true
Answer:
(a) the degree of the polynomial is even, and
(b) the coefficient of the leading term is negative.
