Question

A bag of candy contains 5 red, 4 blue, 6 green, and 3 yellow candies. what is the probability of randomly selecting one candy that is blue or yellow? ( answers 1.)38.9% 2.) 55.6% 3.)16.7 4.)22.2%

Answer 1

Answer:

1) 38.9%

Step-by-step explanation:

There are 18 total pieces of candy, 4 of which are blue, and 3 of which are yellow. So the probability of randomly selecting one blue or one yellow piece of candy is

$\frac{3}{18} + \frac{4}{18} = \frac{7}{18} = 38.9\%$