All categories

2 years ago

Why is the sum of -5 and +5 equal to zero?

Mathematics

2 answers:

Komok [63]2 years ago

8 0

Answer:

- and + cancel each other

Step-by-step explanation:

Sedbober [7]2 years ago

6 0

When adding opposites, it’s called the additives inverse. Because the numbers are opposite the negative and positive signs cancels out

You might be interested in

Write 0.3 as a fraction in simplest form.

s344n2d4d5 [400]

The question is asking to convert the said decimal value in a simplest fraction form, base on my research and further calculation, I would say that the answer would be 3/10. I hope you are satisfied with my answer and feel free to ask for more

6 0

3 years ago

The points in the table lie on a line. Find the slope of the line

8090 [49]

Answer:

1/2

Step-by-step explanation:

Pick two of the x's and y's

The first two columns in the table, the x's are -2 and 0 and the y's are 3 and 4.

The x value changes as a +2 and the y value changes from a +1 from the first two columns. Put the +2 as the denominator and the +1 as the numerator. 1/2

5 0

3 years ago

Find the area of circle o if DCBO is a rectangle and DB measure 10 units

Dmitrij [34]

Answer:

$100\pi$

Step-by-step explanation:

Step 1: Identity the radius.

Since O is the center of the circle, and C and E lie on the circumference, OC and OE are the radii of the circle and thus,

OC=OE.

Step 2: Consider the rectangle.

All diagonals in a rectangle are congruent so this means

DB= OC ( OC is also a diagonal).

Thus, OC= 10 units.

Step 3: Analyze

So this means OE is also 10 units as well.

Since we know the length of the radius, Use the area of circle,

$\pi {r}^{2}$

$\pi( {10}^{2} ) = 100\pi$

So the area of a circle is 100 pi.

3 0

2 years ago

Read 2 more answers

Find the perimeter of the following triangle.

pashok25 [27]

Hello!

To find the perimeter of the triangle, we need to find the length of all the sides using the <u>distance formula</u>.

The distance formula is: $d =\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ .

First, we can find the distance between the points (-3, -1) and (2, -1). The point (-3, -1) can be assigned to $(x_{1},y_{1})$ , and (2, -1) is assigned to $(x_{2},y_{2})$ . Then, substitute the values into the formula.

$d =\sqrt{(2 - (-3))^{2}+ (-1 - (-1))^{2}}$

$d =\sqrt{5^{2}+0^{2}}$

$d =\sqrt{25} = 5$

The distance between the points (-3, -1) and (2, -1) is 5 units.

Secondly, we need to find the distance between the points (2, 3) and (2, -1). Assign those points to $(x_{1},y_{1})$ and $(x_{2},y_{2})$ , then substitute it into the formula.

$d =\sqrt{(2 - 2)^{2}+ (-1 - 3)^{2}}$

$d =\sqrt{0^{2}+(-4)^{2}}$

$d =\sqrt{16} = 4$

The distance between the two points (2, 3) and (2, -1) is 4 units.

Finally, we use the distance formula again to find the distance between the points (-3, -1) and (2, 3). Remember the assign the ordered pairs to $(x_{1},y_{1})$ and $(x_{2},y_{2})$ and substitute!

$d =\sqrt{(2 -(-3))^{2}+ (3 - (-1))^{2}}$