<span>If you plug in 0, you get the indeterminate form 0/0. You can, therefore, apply L'Hopital's Rule to get the limit as h approaches 0 of e^(2+h),
which is just e^2.
</span><span><span><span>[e^(<span>2+h) </span></span>− <span>e^2]/</span></span>h </span>= [<span><span><span>e^2</span>(<span>e^h</span>−1)]/</span>h
</span><span>so in the limit, as h goes to 0, you'll notice that the numerator and denominator each go to zero (e^h goes to 1, and so e^h-1 goes to zero). This means the form is 'indeterminate' (here, 0/0), so we may use L'Hoptial's rule:
</span><span>
=<span>e^2</span></span>
Answer:
C. 342
Step-by-step explanation:
This year, 150% of last year's tickets were sold.
Last year, 228 tickets were sold.
150% as a fraction is 150/100
To find the amount of tickets sold this year, we take the 150/100 and multiply it by 228:
150/100*228= 342 tickets
Answer:
The Possible model is binomial distribution model.
Step-by-step explanation:
The argument that both students cheated in the exam can be proved by a hypothesis that both the students got the same answers incorrectly.
The same incorrect answers prove that both students have cheated on the test.
Therefore the sample of incorrect answers is, n = 8
Thus, the success probability, P = 0.25
Since the given condition has only two outcomes that are choosing the same answer or not choosing the same answer. Thus, this can be solved by the binomial distribution model.
So, binomial distribution with n = 8 and p = 0 .25.
Answer:
Z = 2489/533
Step-by-step explanation:
I went on photo math and solved it
