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2 years ago

(-3) + (+1) = steps of solving

Mathematics

2 answers:

Flauer [41]2 years ago

7 0

Answer:

-2

Step-by-step explanation:

3 - 1 = 2

so it's basically adding 1 to the -3 so it would be -2

viktelen [127]2 years ago

3 0

Answer:

-2

Step-by-step explanation:

Opening brackets,

-3+1=-2

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Solve the inequality 4x − 6 > 6x − 20. (5 points)

liq [111]

Answer:

$14 > 2x$

Step-by-step explanation:

you first have to move 4x to the right side and then add 20 yo the left side to get what i got

4 0

2 years ago

What's the value of given expression :<br><br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B9%7D%20" id="TexFormula1" title=" \

shusha [124]

Answer:

$\sqrt{9} = \sqrt{3 \times 3} = 3 \\ thank \: you$

4 0

2 years ago

Read 2 more answers

Helpppppppppppppppppppppppppp

ddd [48]

Answer:
The last choice is the correct one

Explanation:
We can solve this question using "difference between squares" which has the following general rule:
a^2 - b^2 = (a+b)(a-b)

For the given question:
p^4 - 16 = (p^2 - 4)(p^2 + 4)

Now, p^2 - 4 can be further factorized using difference between squares, therefore:
p^4 - 16 = (p-2)(p+2)(p^2 + 4)

Hope this helps :)

5 0

3 years ago

suppose you have $55 in your bank account. You start saving $10 each week. Your friend has $20 in her account and is saving $15

zhenek [66]

The equation is:
55 + 10 x = 20 + 15 x, where x is number of the weeks.
55 - 20 = 15 x - 5 x
35 = 5 x
x = 35 : 5
x = 7
Answer:
The same amount of money in both accounts will be after 7 weeks.

7 0

2 years ago

If tan (theta) =5/4 and cos (theta) < 0 . Find the other trig. functions.

andrew-mc [135]

Tan(theta) = 5/4
sin(theta)/cos (theta)=5/4
cos(theta)=4sin(theta)/5
sin²(theta)+cos²(theta)=1
sin²(theta)+16sin²(iheta)/25=1 /*25
25 sin²(theta)+16 sin²(theta)=25
sin²(theta)=25/41 /√
sin(theta)= $\frac{-5 \sqrt{41} }{41}$
cos(theta)= $\frac{-4 \sqrt{41} }{41}$
cot(theta)= $\frac{4}{5}$
csc(theta)=1/sin(theta)= $\frac{- \sqrt{41} }{5}$
sec(theta)=1/cos(theta)= $\frac{- \sqrt{41} }{4}$

5 0

2 years ago