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taurus [48]
2 years ago
8

Is this the right answer!! :)

Mathematics
2 answers:
beks73 [17]2 years ago
4 0

Answer:

Option D). Quadrant V is the correct answer.

Step-by-step explanation:

Your answer is correct.

Hope this helps!

Neko [114]2 years ago
4 0

Answer:

Option D) Quadrant V

Step-by-step explanation:

your answer is correct since there are only 4 quadrants in a coordinate plane

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7 0
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Please explain step by step in full process
mafiozo [28]

Answer:

x = 120°

y = 60°

Step-by-step explanation:

✔️since, lines l and m, area parallel, therefore,

x = 120° (they are corresponding angles having matching corners. Thus, corresponding angles are congruent to each other)

✔️x + y = 180° (linear pair angles)

Plug in the value of x

120 + y = 180

Subtract 120 from each side of the equation

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3 years ago
Mrs. Johnson buys 2 chickens. The average weight of the 2 chickens is 4 pounds. One of the chickens is 2 pounds heavier. What is
irakobra [83]
Heaviest chicken is 6 pounds
7 0
3 years ago
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Which of the following is an identity? A. sin2x sec2x + 1 = tan2x csc2x B. sin2x - cos2x = 1 C. (cscx + cotx)2 = 1 D. csc2x + co
Ne4ueva [31]
There are three 'Pythagorean' identities that we can look at and they are

sin²(x) + cos²(x) = 1
tan²(x) + 1 = sec²(x) 
1 + cot²(x) = csc²(x)

We can start by checking each option to see which one would give us any of the 'Pythagorean' identities as its simplest form

Option A:

sin²(x) sec²(x) + 1 = tan²(x) csc²(x)

Rewriting sec²(x) as 1/cos²(x)
Rewriting tan²(x) as sin²(x)/cos²(x)
Rewriting csc²(x) as 1/sin²(x)

We have

sin^{2}(x)[ \frac{1}{ cos^{2}(x) }]+1=[ \frac{ sin^{2}( x)}{ cos^{2} (x)}][ \frac{1}{ sin^{2}(x) } ]
[\frac{ sin^{2}(x) }{ cos^{2}(x) } ]+1= \frac{1}{ cos^{2}(x) }
tan^{2}(x)+1= sec^{2}(x)

Option B:

sin²(x) - cos²(x) = 1

This expression is already in the simplest form, cannot be simplified further

Option C:

[ csc(x) + cot(x) ]² = 1

Rewriting csc(x) as 1/sin(x)
Rewriting cot(x) as cos(x)/sin(x)

We have

[ \frac{1}{sin(x)}+ \frac{cos(x)}{sin(x)}] ^{2} =1
\frac{1}{sin^2(x)}+2( \frac{1}{sin(x)})( \frac{cos(x)}{sin(x)})+ \frac{cos^2(x)}{sin^2(x)}=1csc^2(x)+2csc^2(x)cos(x)+cot^2(x)=1

Option D:

csc²(x) + cot²(x) = 1

Rewriting csc²(x) as 1/sin²(x) and cot²(x) as cos²(x)/sin²(x)

\frac{1}{sin^2(x)}+ \frac{cos^2(x)}{sin^2(x)}=1
\frac{1+cos^2(x)}{sin^2(x)} =1
1+cos^2(x)=sin^2(x)
1=sin^2(x)-cos^2(x)

from our working out we can see that option A simplified into one of 'Pythagorean' identities, hence the correct answer
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3 years ago
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