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Anit [1.1K]
3 years ago
7

Mrs. Johnson buys 2 chickens. The average weight of the 2 chickens is 4 pounds. One of the chickens is 2 pounds heavier. What is

the weight of the heaviest chicken?
Mathematics
2 answers:
irakobra [83]3 years ago
7 0
Heaviest chicken is 6 pounds
saul85 [17]3 years ago
4 0
The heaviest chicken would actually be 4 pounds. Since the average of both chickens is 4, that means they had to do the weight of the chickens added together than divided by two. The only one that would work is 2. So then you add 2 to that and it would be four.
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Which rule explains why these scalene triangles are similar?
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Answer:

D. None of the above; the triangles cannot be proven similar

Step-by-step explanation:

There are no signs that shows the triangles are similar or congruent for given information. So the answer is last option :

D. None of the above; the triangles cannot be proven similar

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How many modes does the following data set have?<br> 5, 5, 6, 7, 8, 12, 12, 12, 150, 150, 150
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2

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What is 38 x 4 = ? <br> i will give away 100 points for next question IF RIGHT
grandymaker [24]

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152

Step-by-step explanation:

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PLZ HELP, AND PLZ EXPLAIN
shutvik [7]

Answer:

C

Step-by-step explanation:

To make it easy let's start by organizing our information :

  • AC=12 AND BD=8
  • ABCD is a rhombus
  • K and L are the midpoints of sides AD and CD
  • we notice that the rhombus ABCD is divided into four right triangles

What do you think of when you hear a right triangle ?

  • The pythagorian theorem !

AC and BD  are khown so let's focus on them .

If we concentrated we can notice that AB and BD are cossing each other in the midpoints . why ?

Simply because they are the diagonals of a rhombus .

ow let's apply the pythagorian theorem :

  • (AC/2)² + (BD/2)² = BC²
  • 6²+4²=52
  • BC²= 52⇒\sqrt{52}=BC

Now we khow that : AB=BC=CD=AD=\sqrt{52}

This isn't enough . Let's try to figure out a way to calculate the length of KL  wich is the base of the triangle

  • KL is parallel to AC
  • k is the midpoint of AD and L of DC

I smell something . yes! Thales theorem

  • KL/AC=DL/DC=DK/AD WE4LL TAKE OLY ONE
  • KL/12=\sqrt{52}/2*\sqrt{52}  
  • KL/12=1/2⇒ KL=6

Now we have the length of the base kl

Now the big boss the height :

  • notice that you khow the length of KL
  • BD crosses kl from its midpoint and DL = \sqrt{52} /2

What I want to do is to apply the pythgorian thaorem to khow the lenght of that small part that is not a part of the height of the triangle . I will call it D

  • DL²=(KL/2)²+D²
  • 52/4= 9+ D²
  • D² = 52/4-9 +4 SO D=2

now the height of the trigle is H= BD-D= 8-2=6

NOw the area of the triangle is :

  • A=(KL*H)/2 ⇒ A= (6*6)/2=18

THE ANSWER IS 18 SQ.UN

5 0
3 years ago
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