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3 years ago

Lines m and n are graphed on the coordinate plane below select all of the statements that are true

Mathematics

2 answers:

Llana [10]3 years ago

6 0

The answers are a,b and c

Bezzdna [24]3 years ago

5 0

Answer:

the answers are: b, c, and e

Step-by-step explanation:

since line m is pointing down, the slope is negative

since line n is pointing up, the slope is positive

since line m's y intercept is 2, and line n's intercept is -3, and 2 is greater than -3, the y intercept for line m is greater than that of line n

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Jasmine filled her bag with 12 strawberries. George filled his bag with 6 times as many strawberries as jasmine. How many strawb

Brilliant_brown [7]

Answer:

There are 72 strawberries in George's bag.

Step-by-step explanation:

Given:

Jasmine filled her bag with 12 strawberries. George filled his bag with 6 times as many strawberries as jasmine.

Now, to find the number of strawberries are in George's bag.

Number of strawberries in Jasmine bag = 12.

George filled his bag with 6 times as many strawberries as jasmine.

So, number of strawberries of George's bag is:

$12\times 6$

$=72.$

Therefore, there are 72 strawberries in George's bag.

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3 years ago

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4 years ago

The lengths of pregnancies are normally distributed with a mean of days and a standard deviation of days. a. Find the probabilit

Alik [6]

Answer:

a) The probability of a pregnancy lasting X days or longer is given by 1 subtracted by the p-value of $Z = \frac{X - \mu}{\sigma}$ , in which $\mu$ is the mean and $\sigma$ is the standard deviation.

b) We have to find X when Z has a p-value of $\frac{a}{100}$ , and X is given by: $X = \mu - Z\sigma$ , in which $\mu$ is the mean and $\sigma$ is the standard deviation.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

In this question:

Mean $\mu$ , standard deviation $\sigma$

a. Find the probability of a pregnancy lasting X days or longer.

The probability of a pregnancy lasting X days or longer is given by 1 subtracted by the p-value of $Z = \frac{X - \mu}{\sigma}$ , in which $\mu$ is the mean and $\sigma$ is the standard deviation.

b. If the length of pregnancy is in the lowest a%, then the baby is premature. Find the length that separates premature babies from those who are not premature.

We have to find X when Z has a p-value of $\frac{a}{100}$ , and X is given by: $X = \mu - Z\sigma$ , in which $\mu$ is the mean and $\sigma$ is the standard deviation.

8 0

3 years ago

Help me out please :)

Alisiya [41]

Answer:

2$ I think

Step-by-step explanation:

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